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Ksenya-84 [330]
3 years ago
11

Alejandro wants to determine the average shoe size of all of the male students in his school. Which sample is likely to yield th

e
most biased results?
every tenth boy on the school's phone list
every member of the boys' basketball team
every boy in a randomly selected ninth-, tenth-, eleventh-, and twelfth-grade gym class
every fifth boy who walks through the front doors of the school in the morning
Mathematics
2 answers:
motikmotik3 years ago
6 0

Answer:

Step-by-step explanation:

every tenth boy on the school’s phone list every member of the boys’ basketball team every boy in a randomly selected ninth-, tenth-, eleventh-, and twelfth-grade gym class every fifth boy who walks through the front doors of the school in the morning

serious [3.7K]3 years ago
4 0

Answer:

b

Step-by-step explanation:

every tenth boy on the school’s phone list every member of the boys’ basketball team every boy in a randomly selected ninth-, tenth-, eleventh-, and twelfth-grade gym class every fifth boy who walks through the front doors of the school in the morning

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Leona [35]

Answer:

The correct option is C

Step-by-step explanation:

A: We know that the lower quartile is 144, and the upper quartile is 129.5 is you add them all up it is going to equal 273.3. So we know that A can now be crossed out.

B: We know that the lower quartile is 146, and that means the upper quartile is 136.5. So adding all of these numbers up we ill get 282.5 So now <u>B can be crossed out</u>

C: The lower quartile is 114 and the upper quartile is 129.5 and when we add those two numbers up we are going to get 243.5. So we are going to keep this number

D: For the last one we know the lower quartile is 214 and upper is 129.5, and when we add this we get 343.5. So we can cross this out and<u> the only one we have left is going to be C</u>

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Answer:

Please read the answers below.

Step-by-step explanation:

Let's calculate the four means between 100 and 135, this way:

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2. Weighted mean:

We will assign equal weight to both numbers : 5

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