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GuDViN [60]
3 years ago
9

Select all that apply to organic compounds. Organic compounds are only found in living things. Organic compounds can be synthesi

zed in a laboratory setting. Organic compounds contain carbon. CO2 is an organic compound. There are hundreds of thousands of organic compounds.
Chemistry
2 answers:
Andreyy893 years ago
7 0

Answer:

Correct options:

Organic compounds can be synthesized in a laboratory setting.

There are hundreds of thousands of organic compounds.

Explanation:

1) Organic compounds are only found in living things: False

Organic compounds are mainly carbon based. Although organic compounds are derived from living things like plants and animals, non-living things like sedimentary rocks are also rich in carbon.

2) Organic compounds can be synthesized in a laboratory setting: True

There are four major categories of organic compounds: carbohydrates, proteins, lipids and nucleic acids all of which can be synthesized in a laboratory.

3) Organic compounds contain carbon: False

Organic compounds are identified by the presence of both carbon and hydrogen (and sometimes other elements like O, N, S).

4)CO2 is an organic compound: False

There are no H atoms, hence CO2 is not organic.

5) There are hundreds of thousands of organic compounds: True

ale4655 [162]3 years ago
6 0
Organic compounds are only found in living things, organic compounds contain carbon, CO2 is an organic compound,
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What is the total amount of kinetic and potential energy of a substance?
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Answer:

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How many kilojoules of energy would be required to heat a 225g block of aluminum from 23.0 C to 73.5 C?
gulaghasi [49]

Answer:

\boxed {\boxed {\sf 10.2 \ kJ}}

Explanation:

We are asked to find how many kilojoules of energy would be required to heat a block of aluminum.

We will use the following formula to calculate heat energy.

q=mc \Delta T

The mass (m) of the aluminum block is 225 grams and the specific heat (c) is 0.897 Joules per gram degree Celsius. The change in temperature (ΔT) is the difference between the final temperature and the initial temperature.

  • ΔT = final temperature - inital temperature

The aluminum block was heated from 23.0 °C to 73.5 °C.

  • ΔT= 73.5 °C - 23.0 °C = 50.5 °C

Now we know all three variables and can substitute them into the formula.

  • m= 225 g
  • c= 0.897 J/g° C
  • ΔT= 50.5 °C

q= (225 \ g )(0.897 \ J/g \textdegree C)(50.5 \textdegree C)

Multiply the first two numbers. The units of grams cancel.

q= (225 \ g  * 0.897 \ J/g \textdegree C)(50.5 \textdegree C)

q= (225   * 0.897 \ J / \textdegree C)(50.5 \textdegree C)

q= (201.825\ J / \textdegree C)(50.5 \textdegree C)

Multiply again. This time, the units of degrees Celsius cancel.

q= 201.825 \ J * 50.5

q= 10192.1625 \ J

The answer asks for the energy in kilojoules, so we must convert our answer. Remember that 1 kilojoule contains 1000 joules.

\frac { 1  \ kJ}{ 1000 \ J}

Multiply by the answer we found in Joules.

10192.1625 \ J * \frac{ 1 \ kJ}{ 1000 \ J}

10192.1625  * \frac{ 1 \ kJ}{ 1000 }

\frac {10192. 1625}{1000} \ kJ

10.1921625 \ kJ

The original values of mass, temperature, and specific heat all have 3 significant figures, so our answer must have the same. For the number we found, that is the tneths place. The 9 in the hundredth place tells us to round the 1 up to a 2.

10.2 \ kJ

Approximately <u>10.2 kilojoules</u> of energy would be required.

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