The final speed of the green ball : 8.5 m/s
<h3>Further explanation</h3>Given
mass of Croquet ball = 0.5 kg
v₁= 10 m/s
v₁'= 1.5 m/s
Required
the final speed
Solution
The law of conservation of momentum
m₁v₁ + m₂v₂ = m₁v₁ '+ m₂v₂' (1=red croquet ball, 2=green croquet ball)
v₂=0 (at rest)
Input the value :
Answer :
The mass of excess mass of ,
are, 1.908 g, 0 g, 12.144 g and 3.74 g respectively.
Explanation : Given,
Mass of = 4.25 g
Mass of = 7.50 g
Molar mass of = 106 g/mole
Molar mass of = 170 g/mole
Molar mass of = 276 g/mole
Molar mass of = 85 g/mole
First we have to calculate the moles of and
.
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 moles of react with 1 mole of
So, 0.044 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
The excess mole of = 0.040 - 0.022 = 0.018 mole
Now we have to calculate the mass of excess mole of .
Now we have to calculate the moles of .
As, 1 moles of react to give 1 moles of
So, 0.044 moles of react to give 0.044 moles of
Now we have to calculate the mass of .
Now we have to calculate the moles of .
As, 2 moles of react to give 2 moles of
So, 0.044 moles of react to give 0.044 moles of
Now we have to calculate the mass of .