A major component of gasoline is octane (C8H18). When octane is burned in air, it chemically reacts with oxygen gas (O2) to prod
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Answer:
The sample size is 601.
Explanation:
Given information:
Confidence interval = 95%
E = 4% = 0.04
From the z table it is clear that the z-value 95% confidence is 1.96.
A researcher wants to determine the proportion of pro-peace students at Rutgers University.
Formula for sample size is
Substitute the given values in the above formula.
Sample size can not be a decimal value. So, round the answer to the next whole number.
Therefore, the sample size is 601.
Explanation:
Let us assume that the ratio for the given reaction is 1:1.
Therefore, we will calculate the moles of as follows.
Moles of solution = molarity × volume (L)
= 0.0440 M × 0.014 L
= 0.000616 moles
Moles of excess EDTA = 0.000616 moles
Also, the initial moles of EDTA will be calculated as follows.
Total initial moles of EDTA = 0.0600 M × 0.025 L
= 0.0015
Therefore, moles of EDTA reacted with will be as follows.
= 0.0015 - 0.000616
= 0.00088 moles
Since, we have supposed a 1 : 1 ratio between and EDTA
.
So, moles of = 0.00088 moles
Now, we will calculate the molarity of as follows.
Molarity of solution =
=
= 0.015 M
Thus, we can conclude that the original concentration of the solution is 0.015 M.