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ch4aika [34]
3 years ago
9

Please help me with that

Mathematics
1 answer:
PtichkaEL [24]3 years ago
7 0
Common solution for each problem:
let
1st point=(x1,y1)
&,
2nd point=(x2,y2),then,

distance between 1st and 2nd point is:
√[(x2-x1)²+(y2-y1)²]

Just replace these x2,y2,x1,y1 with given points and you will get required answer..
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A newspaper carrier has $5.40 in change. He has six more quarters than dimes but five times as many nickles as quarters. How man
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X= number of dimes
x+6= number of quarters
5(x+6)= number of nickels
$5.40= 540 cents

Add the number of each coin and set it equal to the total in cents.


x + (x + 6) + 5(x + 6)= $5.40
multiply 5 by parentheses; change dollar total to cents

x + (x + 6) + (5 * x) + (5 * 6)= 540

x + (x + 6) + 5x + 30= 540
combine like terms

7x + 36= 540
subtract 36 from both sides

7x= 504
divide both sides by 7

x= 72 dimes

x + 6= 78 quarters

5(x + 6)= 390 nickels


CHECK
72 + 78 + 390= 540
540= 540


ANSWER: There are 72 dimes, 78 quarters and 390 nickels.

Hope this helps! :)
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