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sasho [114]
3 years ago
13

Twenty students in class A and 20 students in class B were asked how many hours they took to prepare for an exam.

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0
The mean study time is less for class b then class a
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Solve for Unknown: x/10=43/46.
sergey [27]

Answer:

9

Step-by-step explanation:

x= 430/46

x=9.35 approximately 9( nearest whole number)

4 0
2 years ago
The number of trees in a rainforest decreases each month by 0.5%. The forest currently has 2.5 billion trees. Which expression r
Blababa [14]

Answer:

y=2.5*10^9(0.005^{12 0}) \\\\

Step-by-step explanation:

The above question is in the form of an exponential decay. The equation for an exponential decay is given by:

y=ab^x

where y and x are variables, b < 1, a is the initial value of y (that is the value of y when x = 0).

Let y represent the number of trees left and x represent the number of months. Given that there is currently 2.5 billion trees, therefore a = 2.5 * 10⁹, b = 0.5% = 0.005. The equations becomes:

y=2.5*10^9(0.005^x)\\\\After\ ten\ years(x=10*12\ months=120\ months):\\\\y=2.5*10^9(0.005^{12 0}) \\\\

8 0
3 years ago
PLZ HELP-PICTURE ATTACHED<br> MATHMATICS
Aleksandr [31]

Answer:the frist on

Step-by-step explanation:

there 5 canby bars and there are 8 boxes  so you would do(5x8) divided by s and s= 1  

6 0
3 years ago
Read 2 more answers
X = A 21.6 B 12.9 C 9.1
Artist 52 [7]

Answer:

B: 12.9

Step-by-step explanation:

If A B and C are the alternatives, the answer is B: 12.9

The reason is that the hypotenuse can't be smaller than one of its sides, that eliminates alternative C.

And also, the hypotenuse can't be bigger than segments AC + BC, since the side AC is bigger and AC measures 10.8, the hypotenuse would have to measure < 21.6

Any questions, comment.

6 0
3 years ago
Read 2 more answers
Given: ΔАВС, m∠ACB = 90°,m∠ACD = 30°,AD = 8 cm. Find: CD, Perimeter ΔABC <br><br> Please solve!
sukhopar [10]
If m ACD = 30 => m DCB = 60.
In triangle ACD:
sin 30^{o}=sin  \frac{AD}{AC} =\ \textgreater \   \frac{1}{2}  =  \frac{8}{AC} =\ \textgreater \  AC=16&#10;
CD= 8 \sqrt{3}
BC= 16\sqrt{3}
AC^{2}+CB^{2}=AB^{2} => AB=\sqrt{1024}=32.
=> P=16+32+16 \sqrt{3}=48 +16 \sqrt{3}.

8 0
4 years ago
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