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sasho [114]
3 years ago
13

Twenty students in class A and 20 students in class B were asked how many hours they took to prepare for an exam.

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0
The mean study time is less for class b then class a
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Please explain how you got your answers! (: Solve the problem by using the counting principle.
Natasha2012 [34]
A. The number of fabric-pattern-color combinations is 4 * 13 * 9 = 468

B. P(1st choice) = no of novels / total books = 3/6 = 1/2
    P(2nd choice) = no of remaining novels/ total remaining books = 2/5
    P(both novels) = 1/2 * 2/5 = 1/5          (without replacement assumed)

C. P(1st choice) = no of biographies / total books = 2/6 = 1/3
    P(2nd choice) = no of remaining biographies/ total remaining books =        1/5
    P(both biographies) = 1/3 * 1/5 = 1/15          (without replacement                assumed)

D. P(1st choice) = no of history books / total books = 1/6
    P(2nd choice) = no of novels/ total remaining books = 3/5
    P(a history, then a novel) = 1/6 * 3/5 = 1/10          (without replacement assumed)
7 0
3 years ago
11x + 10y - 8x - 12y<br><br> (a) x + -2y<br> (b) 3x + 2y<br> (c) -x + 2y<br> (d) 3x + -2y
svetoff [14.1K]

Answer:

d) 3x+-2y

Step-by-step explanation:

combine like terms of x and y

11x-8x=3x

10x-12x=-2y

brainliest?

8 0
3 years ago
Rafael ha comprado 185,8 kg. de manzanas y 300,2 kg. de naranjas. ¿Cuánto más pesan las naranjas que las manzanas? ¿Cuánto pesa
Anon25 [30]

Answer:

a.114.4kg

b. 486kg

Step-by-step explanation:

Firstly , we want to know the value with which the apples weigh more than the oranges

To calculate this, we simply subtract the weight of the oranges from that of the apple

Mathematically, that would be ;

300.2-185.8 = 114.4kg

The total weight of the things bought is calculated by adding both weights together

That would be 185.8 + 300.2 = 486 kg

8 0
3 years ago
If log65 = 1.812 what is the value of log(base 1000)65 ? 0.0604 0.604 0.1812 0.001812
ioda
If we have:

logₐy = (logₓy) / (logₓa)       By change of base formula.

log₁₀65 = (log₁₀₀₀65) / (log₁₀₀₀10)

(log₁₀₀₀65)  = log₁₀65 * (log₁₀₀₀10)

log(₁₀₀₀10) =  1/ (log₁₀1000) = 1/(log₁₀10³) = 1/3

(log₁₀₀₀65)  = (log₁₀65) * (log₁₀₀₀10)

(log₁₀₀₀65)  = 1.812 * (1/3)       

(log₁₀₀₀65)  = 0.604

I hope this helps.
8 0
3 years ago
I stg this is the 3rd time i've asked this question but please help me
Evgen [1.6K]

Answer:

The FitnessGram™ Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20 meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. Ding  A single lap should be completed each time you hear this sound. Ding  Remember to run in a straight line, and run as long as possible. The second time you fail to complete a lap before the sound, your test is over. The test will begin on the word start. On your mark, get ready, ding

Step-by-step explanation:

5 0
3 years ago
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