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jolli1 [7]
4 years ago
14

The position of a simple harmonic oscillator is given by x left-parenthesis t right-parenthesis equals left-parenthesis 0.50 mri

ght-parenthesis cosine left-parenthesis startfraction pi over 3 endfraction t right-parenthesis where t is in seconds. what is the maximum velocity of this oscillator?
Physics
1 answer:
polet [3.4K]4 years ago
4 0
The specified displacement is
x(t)=(0.50\,m)cos( \frac{ \pi t}{3} )

The velocity is the derivative f displacement with respect to time.
The velocity is
v(t)=-0.50( \frac{ \pi }{3} )sin( \frac{ \pi t}{3} )

The maximum valu of v occurs when the sine functin is 1 or -1.
Therefore, the maximum velocity is
vmax = 0.5(π/3) = 0.524 m/s

Answer: 0.524 m/s
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Answer:

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Explanation:

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Hi there!

\large\boxed{KE =1.245 J}}

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