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maksim [4K]
3 years ago
7

A class contains 13 boys and 17 girls. of the girls, 25% have blond hair. what percentage of the class are blonds

Mathematics
2 answers:
Zigmanuir [339]3 years ago
7 0
For this case, we first look for the number of blonde girls.
 We have then:
 (25/100) * (17) = 4.25

 We are now looking for the percentage of the class with blonde hair.
 For this, we make the following rule of three:
 30 --------------> 100%
 4.25 -----------> x
 From here, we clear the value of x.
 We have then:
 x = (4.25 / 30) * (100)

x = 14.2%
 Answer:
 
14.2% of the class are blonds
vodomira [7]3 years ago
7 0

Answer:

14.2% of the class are blonds.

Step-by-step explanation:

We have been given that a class contains 13 boys and 17 girls. of the girls, 25% have blond hair.

First of all, we will find 25% of 17.

\frac{25}{100}\cdot 17=0.25\cdot 17=4.25

Now, we will find 4.25 is what percent of total students (13+17=30).

Let 4.25 be x percent of 30. We can represent this information in an equation as:

\frac{x}{100}\cdot 30=4.25

Now, let us solve for x.

\frac{x}{100}\cdot 30\cdot \frac{100}{30}=4.25\cdot \frac{100}{30}

x=\frac{425}{30}

x=14.166

x\approx 14.2

Therefore, 14.2 percentage of the class are blonds.

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Answer:

A

Step-by-step explanation:

Since the shape and vertex x coordinate of both graphs are the same, the only difference is the vertical displacement. Since the blue graph is 4 above the origin and the red graph is 1 above the origin, its graph is:

g(x)=1-x^2

Hence, the correct answer is choice A. Hope this helps!

4 0
4 years ago
Solve for x. x+3/4=5
GaryK [48]

Answer

\begin{gathered} Given\text{ }x+\frac{3}{4}=5 \\ x=5-\frac{3}{4} \end{gathered}x=4\frac{1}{4}

Therefore, x = 4 1/4

8 0
1 year ago
In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study
DIA [1.3K]

Answer:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

Step-by-step explanation:

Information provided

X_{1}=1642 represent the number of smokers from the sample in 1995

X_{2}=1415 represent the number of smokers from the sample in 2010

n_{1}=4276 sample from 1995

n_{2}=3908 sample from 2010  

p_{1}=\frac{1642}{4276}=0.384 represent the proportion of smokers from the sample in 1995

p_{2}=\frac{1415}{3908}=0.362 represent the proportion of smokers from the sample in 2010

\hat p represent the pooled estimate of p

z would represent the statistic    

p_v represent the value for the pvalue

System of hypothesis

We want to test the equality of the proportion of smokers and the system of hypothesis are:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

The statistic is given by:

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{1642+1415}{4276+3908}=0.374  

Replacing the info given we got:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

7 0
3 years ago
Estimate the answer to 341÷28
Dmitriy789 [7]
To estimate this question, you can round the numbers to be compatible, to make it easier for yourself. The numbers should be able to be divided cleanly, as this is an estimate, not the actual problem solving. You could, for example, round 341 to 300, and 28 to 30, and divide them to get 10.
Hope that helped.
3 0
3 years ago
Read 2 more answers
Please help me on this question 20 points
Leokris [45]

Answer:

\left[\begin{array}{cc}10\\24\end{array}\right]

Step-by-step explanation:

Trial and error lol

7 0
2 years ago
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