1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maksim [4K]
3 years ago
7

A class contains 13 boys and 17 girls. of the girls, 25% have blond hair. what percentage of the class are blonds

Mathematics
2 answers:
Zigmanuir [339]3 years ago
7 0
For this case, we first look for the number of blonde girls.
 We have then:
 (25/100) * (17) = 4.25

 We are now looking for the percentage of the class with blonde hair.
 For this, we make the following rule of three:
 30 --------------> 100%
 4.25 -----------> x
 From here, we clear the value of x.
 We have then:
 x = (4.25 / 30) * (100)

x = 14.2%
 Answer:
 
14.2% of the class are blonds
vodomira [7]3 years ago
7 0

Answer:

14.2% of the class are blonds.

Step-by-step explanation:

We have been given that a class contains 13 boys and 17 girls. of the girls, 25% have blond hair.

First of all, we will find 25% of 17.

\frac{25}{100}\cdot 17=0.25\cdot 17=4.25

Now, we will find 4.25 is what percent of total students (13+17=30).

Let 4.25 be x percent of 30. We can represent this information in an equation as:

\frac{x}{100}\cdot 30=4.25

Now, let us solve for x.

\frac{x}{100}\cdot 30\cdot \frac{100}{30}=4.25\cdot \frac{100}{30}

x=\frac{425}{30}

x=14.166

x\approx 14.2

Therefore, 14.2 percentage of the class are blonds.

You might be interested in
Leon drew AABC and ADEF so that ZA: LD, ZB: LE, AB = 4, and DE = 8.
yulyashka [42]

Answer:

A. similar - AA

there's two corresponding angle that are equal!

4 0
3 years ago
2 An art studio charges $65 per month for art lessons. There is also an additional supply fee of $25 at the time of registration
Bond [772]

Answer:

The equation should be, <em><u>65m+25=c</u></em>

3 0
3 years ago
Read 2 more answers
Write words to match the expression
Readme [11.4K]
Three plus the product of four times twelve
5 0
3 years ago
Read 2 more answers
Approximate pi plus the square root of 70 to the nearest hundredth.
stich3 [128]

Answer:

  11.51

Step-by-step explanation:

In general, a calculator is required to evaluate the irrational sum ...

  π + √70

<h3>Calculator result</h3>

The result from a readily-available online calculator is shown in the attachment.

  π + √70 ≈ 11.51

__

<em>Additional comment</em>

You have probably memorized pi to several digits: 3.1416. To obtain the required estimate means you need to approximate √70 to about the same level of precision.

For a number n = a² +b, the square root can be approximated by the continued fraction ...

  √n ≈ a +b/(2a +b/(2a +...))

Effectively, the root (r) can be iterated from the recursive formula ...

  r' = a +b/(a +r)

For √70, we have 70 = 8² +6   ⇒   a=8, b=6

If the initial approximation of the root is r0≈a=8, then a couple of iterations gives ...

  r1 = 8 + 6/(8 +r0) = 8 + 6/(8 +8) = 8 3/8

  r2 = 8 + 6/(8 +r1) = 8 +6/(8 +8 3/8) = 8 48/131

This has sufficient accuracy for the purpose. The decimal equivalent of the sum then becomes ...

  3.1416 +8.3664 = 11.5080 ≈ 11.51

5 0
2 years ago
The planets in our solar system do not travel in circular paths. Rather, their orbits are elliptical. The Sun is located at a fo
qwelly [4]

1. The distance between the perihelion and the aphelion is 116 million miles

2. The distance from the center of Mercury’s elliptical orbit and the Sun is 12 million miles

3. The equation of the elliptical orbit of Mercury is \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

4. The eccentricity of the ellipse is 0.207 to the nearest thousandth

5. The value of the eccentricity tell you that the shape of the ellipse is near to the shape of the circle

Step-by-step explanation:

Let us revise the equation of the ellipse is

\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 , where the major axis is parallel to the x-axis

  • The length of the major axis is 2a
  • The coordinates of the vertices are (± a , 0)
  • The coordinates of the foci are (± c , 0) , where c² = a² - b²

∵ The Sun is located at a focus of the ellipse

∴ The sun located ate c

∵ The perihelion is the point in a planet’s orbit that is closest to the

   Sun ( it is the endpoint of the major axis that is closest to the Sun )

∴ The perihelion is located at the vertex (a , 0)

∵ The closest Mercury comes to the Sun is about 46 million miles

∴ The distance between a and c is 46 million miles

∵ The aphelion is the point in the planet’s orbit that is furthest from

   the Sun ( it is the endpoint of the major axis that is furthest from

   the Sun )

∴ The aphelion is located at the vertex (-a , 0)

∵ The farthest Mercury travels from the Sun is about 70 million miles

∴ The distance from -a to c is 70 million miles

∴ The distance between the perihelion and the aphelion =

   70 + 46 = 116 million miles

1. The distance between the perihelion and the aphelion is 116 million miles

∵ The distance between the perihelion and the aphelion is the

  length of the major axis of the ellipse

∵ The length of the major axis is 2 a

∴ 2 a = 116

- Divide both sides by 2

∴ a = 58

∴ The distance from the center of Mercury’s elliptical orbit to the

   closest end point to the sun is 58 million miles

∵ The distance between the sun and the closest endpoint is

   46 million miles

∴ The distance from the center of Mercury’s elliptical orbit and

   the Sun = 58 - 46 = 12 million miles

2. The distance from the center of Mercury’s elliptical orbit and the Sun is 12 million miles

∵ The major axis runs horizontally

∴ The equation is \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1

∵ a = 58

∵ c is the distance from the center to the focus of the ellipse

∴ c = 12

∵ c² = a² - b²

∴ (12)² = (58)² - b²

- Add b² to both sides

∴ (12)² + b² = (58)²

- Subtract (12)² from both sides

∴ b² = (58)² - (12)² = 3220

- Substitute these values in the equation

∴ \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

3. The equation of the elliptical orbit of Mercury is \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

The eccentricity (e) of an ellipse is the ratio of the distance from the

center to the foci (c) and the distance from the center to the

vertices (a) ⇒ e=\frac{c}{a}

∵ c = 12

∵ a = 58

∴ e=\frac{12}{58} = 0.207

4. The eccentricity of the ellipse is 0.207 to the nearest thousandth

If the eccentricity is zero, it is not squashed at all and so remains a circle.

If it is 1, it is completely squashed and looks like a line

∵ The eccentricity of the ellipse is 0.207

∵ This number is closed to zero than 1

∴ The shape of the ellipse is near to the shape of the circle

5. The value of the eccentricity tell you that the shape of the ellipse is near to the shape of the circle

Learn more:

You can learn more about conics section in brainly.com/question/4054269

#LearnwithBrainly

5 0
3 years ago
Other questions:
  • Standard form for y=2-3x
    10·1 answer
  • Janina spent 3/4 of her allowance at the mall of the money spent at the mall half of that was spent on earphones what part of he
    15·2 answers
  • Q=p(r+s) solve for p
    14·1 answer
  • What’s the average of 230, 155, 320, 400, and 325
    7·1 answer
  • Which equation shown below represents the equation of the inverse of the quadratic function shown below?
    9·2 answers
  • The amounts of e-waste generated in a region during two years were 14,200,000 tons and 10,700,000 tons. What was the total e-was
    6·2 answers
  • Plans for a new park call for gardens directly across the sidewalk from each other to be congruent. This computer printout shows
    11·1 answer
  • 70,000,000write the number in the form standard
    13·1 answer
  • If q is the midpoint of segment PR, find the coordinates of R if P (11,-2) and Q (4,3) ​
    6·1 answer
  • Given: x + 2 &lt; -5. Choose the solution set.
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!