Explanation:
Since, the given reaction is as follows.

Initial: 36.1 atm 0 0
Change: 2x x x
Equilibrium: (36.1 - 2x) x x
Now, expression for
of this reaction is as follows.
![K_{p} = \frac{[N_{2}][O_{2}]}{[NO]^{2}}](https://tex.z-dn.net/?f=K_%7Bp%7D%20%3D%20%5Cfrac%7B%5BN_%7B2%7D%5D%5BO_%7B2%7D%5D%7D%7B%5BNO%5D%5E%7B2%7D%7D)
As the initial pressure of NO is 36.1 atm. Hence, partial pressure of
at equilibrium will be calculated as follows.
![K_{p} = \frac{[N_{2}][O_{2}]}{[NO]^{2}}](https://tex.z-dn.net/?f=K_%7Bp%7D%20%3D%20%5Cfrac%7B%5BN_%7B2%7D%5D%5BO_%7B2%7D%5D%7D%7B%5BNO%5D%5E%7B2%7D%7D)
x = 18.1 atm
Thus, we can conclude that partial pressure of
at equilibrium is 18.1 atm.
Answer:
The answer is D, I would type it out but it is to long and I'm kind of lazy, but anyways! Your answer is D
Hope This Helps!
Answer:
sodium ions and chloride ions
chloride ion
sodium ion
Explanation:
Ionic substances are composed of ions. When you dissolve an Ionic substance in water, the ions that compose the substance together with water molecules are present in solution.
Hence, when sodium chloride is dissolved in water, sodium ions and chloride ions are released in solution.
Water has a dipole moment. Hence, the chloride ions are attracted to hydrogen (the positive end of the dipole) while sodium ions are attracted to oxygen (the negative end of the dipole).
This is how the solid is dissolved in water.
If the difference in electronegativtiy for the atoms in a bond are greater than 0.4,we consider the bond polar, if the electronegativity is less than 0.4, we consider it non polar. if there are no polar bonds, the molecule is non polar.
potassium is just below the sodium in periodic table in s group !
so the valence electron of sodium and potassium is same and that is 1