Answer:
x=1
Step-by-step explanation:
I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).
Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system
- y + 3z = -2
y + z = -2
-----------------
4z = -4, so z = -1.
Next, multiply the 3rd equation by 2: You'll get -2x + 2y + 2z = -2.
Add this result to the first equation. The 2x terms will cancel, leaving you with the system
2y + 2z = -2
y + z = 4
This would be a good time to subst. -1 for z. We then get:
-2y - 2 = -2. Then y must be 0. y = 0.
Now subst. -1 for z and 0 for y in any of the original equations.
For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.
Then a tentative solution is (-3, -1, 0).
It's very important that you ensure that this satisfies all 3 of the originale quations.
At first we will find the slope of the line that <span>passes through the points A and B
</span>
<span>A ( -10,8), B(2,3)
slope = (Δy)/(Δx) = (3-8)/(2-(-10)) = -5/12
the require line is parallel to the line </span><span><span>passes through the points A and B
</span>∴ the slope of the line </span><span>that passes through Point X = -5/12
and have a general form
y = m x + c
where m is the slope and c is constant
the constant can be calculated by substituting with the point x (-5,10) in the equation of general form
∴ 10 = (-5/12)*-5 + c
c = 10 - 25/12 = 95/12
∴ y = (-5/12)x +95/12 ⇒⇒⇒⇒ multiplying the equation by 12
∴ 12y = -5x +95
</span>
Answer: Assuming it means slope-intercept, the answer would be y=-2x+9
