Calculate the molarity of a solution that contains 0.250 moles of kf in 0.500 l of water

1 answer:

4 0

Molarity can be defined as the number of moles of solute in 1 L of solution.

M = n/V

Where M is the molarity of the solution (M or mol/L), n is the moles of the solute (mol) and V is the volume of the solution (L).

Here, solute is KF.

n = 0.250 mol
V = 0.500 L
M = ?

By applying the formula,
M = 0.250 mol / 0.500 L
M = 0.500 mol/L

Hence, the molarity of KF solution is 0.500 mol/L.

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The mole fraction of hcl in a solution prepared by dissolving 5.5 g of hcl in 200 g of c2h6o is ________. the density of the sol

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all that we search for is the number of mole of HCl and the number of mole of C2H6O

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M(HCl) = 1+ 36.5= 37.5

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