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grin007 [14]
3 years ago
13

1. Your friend has a balloon that can hold a volume of 5 L. If she added a 3 mol of CO2 gas at a pressure of 0.90 atm, what is t

he temperature of the balloon?
Chemistry
1 answer:
masha68 [24]3 years ago
6 0

Answer:

I don't <u>understand</u><u> </u><u>your</u><u> </u><u>question</u><u> </u>

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HElp i am stuck and i am not sure
alexandr1967 [171]

Answer:

B

Explanation:

hope this helps...

7 0
2 years ago
To make 2.00 L of 0.300 M sulfuric acid, how many mL of a 1.00 M stock solution should be used?
Tamiku [17]
We are given with
M1 = 1.00 M

M2 = 0.300 M
V2 = 2.00 L

We are asked to get V1

Using material balance
M1 V1 = M2 V2
Substituting the given values
1.00 V1 = 0.300 M (2.00 L)
V1 = 0.600 L or 600 mL
THe volume needed is 600 mL<span />
3 0
3 years ago
PLEASE I NEED YOUR HELP, I WILL GIVE 10 POINTS PLEASEEEEE
Cerrena [4.2K]

Answer:

Erosion

Explanation:

3 0
2 years ago
The reaction is first order in cyclopropane and has a measured rate constant of k=3.36×10−5 s−1 at 720 k. if the initial cyclopr
sergey [27]

Answer:

0.0277 M.

Explanation:

The integral rate law of a first order reaction:

<em>Kt = ln ([A₀]/[A]),</em>

where, k is the rate constant of the reaction <em>(k = 3.36 × 10⁻⁵ s⁻¹)</em>,

t is the time of the reaction <em>(t = 235.0 min = 14100 s)</em>,

[A₀] is the initial concentration of cyclopropane <em>([A₀] = 0.0445 M)</em>

<em>∵ Kt = ln ([A₀]/[A]),</em>

∴ (3.36 × 10⁻⁵ s⁻¹)(14100 s) = ln (0.0445 M)/[A]

Taking the exponential of both sides:

1.6 = (0.0445 M)/[A]

<em>∴ [A] = (0.0445 M)/1.6 = 0.0277 M.</em>

<em />

6 0
3 years ago
A force of 100 newtons is applied to a box at an angle of 36º with the horizontal. If the mass of the box is 25 kilograms, what
notka56 [123]

Answer:

a_x=4.944m/s^2

Explanation:

Hello,

Based on the acting force that is applied horizontally, one can propose the following equation based on Newton's laws:

F=ma

Nevertheless, since we've got a angled force, it becomes:

F=macos\theta

In this case, cos\theta accounts for the formed angle, so the horizontal acceleration turns out into:

a_x=\frac{F}{mcos\theta}=\frac{100kg*\frac{m}{s^2} }{25kgcos(36^0)}=4.944m/s^2

Best regads.

5 0
3 years ago
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