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77julia77 [94]
3 years ago
10

Calculate the period (T) of uniform circular motion if the velocity is 40.0 m/s and centripetal acceleration is 20.0 m/s2.

Physics
1 answer:
kirill [66]3 years ago
3 0
T is the time for a whole round.

centripetal acceleration = V^2/R,

20 = 40^2 / R, find R = 40^2/20 = 40*40/20 = 80 m, right?

Now, one round is L = 2*pi*R = 2*pi*80 = 160*pi

And T = L/v (distance/speed) = 160*pi/40 = 4*pi seconds, or ~ 12.57 s
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When you set a heavy bag down on the ground, you are doing negative work on it.

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An atomic scients was studying an atom and through experimentation found that the total negative charge of the
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this atom has nine electrons

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since electrons are found outside the nucleus of an atom and they are negatively charged

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3 years ago
Theo made a list of the properties of electromagnetic waves. Identify the mistake in the list. Electromagnetic Wave Properties 1
lapo4ka [179]

Answer:

Line 3 has a mistake.

Explanation:

Electromagnetic waves consist of oscillations of electric and magnetic fields that oscillate perpendicular to the each other. Therefore, Line 1 is correct.

Also, the fields in an electromagnetic waves oscillate perpendicular to the direction of propagation of the wave: therefore, they are transverse waves. So Line 2 is also correct.

Electromagnetic waves, contrary to mechanical waves, do not need a medium to propagate: so, they can also travel through a vacuum. Therefore, Line 3 is wrong.

Finally, all electromagnetic waves travel through a vacuum at the same speed, called speed of light:

c=3\cdot 10^8 m/s

So, Line 4 is also correct.

3 0
3 years ago
Read 2 more answers
A 1.5-kg block slides at rest starts sliding down a snow-covered hill Point A, which has an altitude of 10 m. There is no fricti
damaskus [11]

Answer:

the speed of the block when it reaches point B is 14 m/s

Explanation:

Given that:

mass of the block slides = 1.5 - kg

height = 10 m

Force constant  = 200 N/m

distance of rough surface patch = 20 m

coefficient of kinetic friction = 0.15

In order to determine the speed of the block when it reaches point B.

We consider the equation for the energy conservation in the system which can be represented by:

\dfrac{1}{2}mv^2=mgh

\dfrac{1}{2}v^2=gh

v^2=2 \times g \times   h

v^2=2 \times 9.8 \times   10

v=\sqrt{2 \times 9.8 \times   10

v=\sqrt{196

v = 14 m/s

Thus; the speed of the block when it reaches point B is 14 m/s

7 0
3 years ago
You weigh 730N. What would you weigh if the earth were six times as massive as it is and its radius were four times its present
Ber [7]

The new weight is 273.8 N

Explanation:

The weight of an object on Earth is given by

W=mg

where

m is the mass of the object

g is the acceleration of gravity

The acceleration of gravity at the Earth's surface can be rewritten as

g=\frac{GM}{R^2}

where

G is the gravitational constant

M is the Earth's mass

R is the Earth's radius

Substituting into the previous equation,

W=\frac{GMm}{R^2}

We said that in normal conditions, the weight of the person is 730 N:

W=\frac{GMm}{R^2}=730 N

Later, we are said that:

  • The mass of the Earth increases by a  factor of 6, M'=6M
  • The radius of the Earth increases by a factor of 4, R'=4R

Substituting into the equation, we find the new weight of the person in these conditions:

W'=\frac{G(6M)m}{(4R)^2}=\frac{6}{16}(\frac{GMm}{R^2})=\frac{3}{8}W

So, the new weight is 3/8 of the original weight, therefore:

W'=\frac{3}{8}(730)=273.8 N

Learn more about gravity:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

3 0
3 years ago
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