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maxonik [38]
3 years ago
10

A coin is dropped in a 15.0 m deep well.

Physics
1 answer:
labwork [276]3 years ago
7 0

Answer:

t = 1.75

t = 0.04

Explanation:

a)

For part 1 we want to use a kenamatic equation with constant acceleration:

X = 1/2*a*t^2

isolate time

t = sqrt(2X / a)

Plugin known variables. Acceleration is the force of gravity which is 9.8 m/s^2

t = sqrt(2*15m / 9.8m/s^2)

t = 1.75 s

b)

The speed of sound travels at a constant speed therefore we don't need acceleration and can use the equation:

v = d / t

isolate time

t = d / v

plug in known variables

t = 15m / 340m/s

t = 0.04 s

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Define the term mid-ocean ridge in simple, easy-to-understand words. Thanks :)
Likurg_2 [28]
According to wikipedia <em>a mid-ocean ridge is an underwater mountains system formed by tectonic plates.

</em>Happy studying!<em>
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6 0
4 years ago
A 0.18-kg ball on a stick is whirled on a vertical circle at a constant speed. When the ball is at the three o’clock position, t
Stells [14]

Answer:

a) 17 N

b) 21 N

Explanation:

At the 3 o'clock position, the sum of the forces towards the center is:

∑F = ma

T = m v² / r

19 = m v² / r

At the 12 o'clock position, the sum of the forces towards the center is:

∑F = ma

T + mg = m v² / r

T + (0.18)(9.8) = 19

T = 17.2 N

At the 6 o'clock position, the sum of the forces towards the center is:

∑F = ma

T − mg = m v² / r

T − (0.18)(9.8) = 19

T = 20.8 N

Rounding to two significant figures, the tensions are 17 N and 21 N.

7 0
4 years ago
If a ball drops from 10ft after 5 seconds how high would the ball be. (For every second the ball loses 3ft) a bounce is half of
nlexa [21]
5ft I took the quiz/test.
3 0
3 years ago
Write the equation of a wave traveling along the +x-axis with an amplitude of 0.02 m, a frequency of 440 Hz, and a speed of 330m
Airida [17]

The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)

<u>Explanation:</u>

Given data

Amplitude 0.02 m , Frequency= 440 Hz ,Speed = 330 m/s

The equation  format is written as,

y =   A   sin (       k        x  –   ω     t)

We need the value of  A, k, x -ω t

<u>1. Find the k value</u>

v     =  f ×λ

330 = 440×λ

   k = 2π×λ

k = 880 π /330  m-1

440 ×2π = w

<u>2. Find the ω  value</u>

f×2π =ω

ω = 880 π  s-1

<u>3. Find the A value</u>

we get A value from the given data

A = 0.02 m

By the formula,

y =   A   sin (       k        x  –   ω     t)

Substitute the values we get the equation,

y = 0.02 sin (880π/330 x – 880 πt)

The equation of the wave travelling along the +x-axis is y = 0.02 sin (880π/330 x – 880 πt)

8 0
3 years ago
Two charged particles are a distance of 1.72 m from each other. One of the particles has a charge of 7.03 nC, and the other has
MaRussiya [10]

A. The magnitude (in N) of the electric force that one particle exerts on the other is 8.60×10⁻⁸ N

B. The force is repulsive

<h3>A. How to determine the magnitude of the electric force</h3>

From the question given above, the following data were obtained:

  • Charge 1 (q₁) = 7.03 nC = 7.03×10¯⁹ C
  • Charge 2 (q₂) = 4.02 nC = 4.02×10¯⁹ C
  • Electric constant (K) = 9×10⁹ Nm²/C²
  • Distance apart (r) = 1.72 m
  • Force (F) =?

The magnitude of the electric force can be obtained by using the Coulomb's law equation as shown below:

F = Kq₁q₂ / r²

F = (9×10⁹ × 7.03×10¯⁹ × 4.02×10¯⁹) / (1.72)²

F = 8.60×10⁻⁸ N

<h3>B. How to determine whether the force is attractive or repulsive</h3>

From the question given, we were told that:

  • Charge 1 (q₁) = 7.03 nC
  • Charge 2 (q₂) = 4.02 nC

Since both charge are positive, then the force attraction between them is repulsive as like charges repels and unlike charges attracts

Learn more about Coulomb's law:

brainly.com/question/506926

#SPJ1

4 0
2 years ago
Read 2 more answers
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