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3 years ago

Rosa records the distance that a toy car rolls and the time it takes to cover the distance. What scientific practice is this?

Physics

2 answers:

suter [353]3 years ago

8 0

collecting data...............................

Sergio039 [100]3 years ago

3 0

Rosa is conducting the scientific practice of observation.

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Wave crests in a pond are separated by 0.2m . The period of these waves is 0.2 s . What is the speed at which these waves travel

Ne4ueva [31]

1m per minute

or .5 m per 30 seconds

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3 years ago

a falling skydiver slows from a speed of 52 m/s to 8 m/s in 0.8 sec as the parachute opens. what is the diver's acceleration and

Cloud [144]

I found the answers here. Hope this helps you! https://1.cdn.edl.io/sJTle6yxt3qVq7jHfdHRZJ3Xogj7ps6swBO9umNcZ6PO3SMN.docx

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3 years ago

As you travel from Detroit in a certain direction, the outside temperature, T (in degrees), depends on your distance, d (in mile

Ber [7]

Answer:

a) $\Delta T= 100^{\circ}C$

b) $\bigtriangledown T=1^{\circ}C.mile^{-1}$

c) $\bigtriangledown T_4=1^{\circ}C.mile^{-1}$

d) $\bigtriangledown T_4=1^{\circ}C.mile^{-1}$

Explanation:

Given is the data of variation of temperature with respect to the distance traveled:

Temperature T as a function of distance d:

$T=(d+30) ^{\circ}C$ ...................................(1)

(a)

Total change in temperature from the start till the end of the journey:

$\Delta T= T_f-T_i$ ..............................(2)

where:

$T_f$ = final temperature

$T_i$ = initial temperature

∵In the start of the journey d = 0 miles & at the end of the journey d = 100 miles.

So, correspondingly we have the eq. (2) & (1) as:

$\Delta T= (100+30)-(0+30)$

$\Delta T= 100^{\circ}C$

(b)

Now, the average rate of change of the temperature, with respect to distance, from the beginning of the trip to the end of the trip be calculated as:

$\bigtriangledown T=\frac{\Delta T}{\Delta d}$ ......................(3)

where:

$\Delta d$ = change in distance

$\bigtriangledown T=$ change in temperature with respect to distance

putting the respective values in eq. (3)

$\bigtriangledown T=\frac{100}{100}$

$\bigtriangledown T=1^{\circ}C.mile^{-1}$

(c)

comparing the given function of the temperature with the general equation of a straight line:

$y=m.x+c$

We find that we have the slope of the equation as 1 throughout the journey and therefore the rate of change in temperature with respect to distance remains constant.

$\bigtriangledown T_4=1^{\circ}C.mile^{-1}$

(d)

comparing the given function of the temperature with the general equation of a straight line:

$y=m.x+c$

We find that we have the slope of the equation as 1 throughout the journey and therefore the rate of change in temperature with respect to distance remains constant.

$\bigtriangledown T_4=1^{\circ}C.mile^{-1}$

4 0

3 years ago

Starting from rest, a 88-kg firefighter slides down a fire pole. The average frictional force exerted on him by the pole has a m

Cloud [144]

Answer:h=7.22 m

Explanation:

Given

mass of firefighter $m=88 kg$

Frictional Force $F=800 N$

average speed at bottom $v=3.2 m/s$

Let h be the height of Pole

net force on Firefighter is

$F_{net}=88\times 9.8-800=62.4$

therefore net acceleration is

$a_{net}=\frac{62.4}{88}=0.709 m/s^2$

using $v^2-u^2=2ah$

here $v=3.2 m/s$

$u=0$

$(3.2)^2-0=2\times 0.709\times h$

$h=\frac{10.24}{1.418}$

$h=7.22 m$

3 0

3 years ago

How do catalysts speed up reactions please help quickly

MissTica

How do catalysts speed up reactions ?

by reducing the amount of energy required for the reaction to occur. other factors such as catalysts' ability to speed a process are temperature, concentration

8 0

3 years ago

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