You are given the mass of a sphere that is 26 kg sphere and it is released from rest when θ = 0°. You are also given the force of the spring that is F = 100 N. You are asked to find the tension of the spring. Imagine that the sphere is connected to a spring. The spring exerts a tension and the spring exerts gravitational pull. This will follow the second law of newton.
T - F = ma
T = ma + F
T = 26kg (9.81m/s²) + 100 N
T = 355.06 N
Complete question:
Point charges q1=- 4.10nC and q2=+ 4.10nC are separated by a distance of 3.60mm , forming an electric dipole. The charges are in a uniform electric field whose direction makes an angle 36.8 ∘ with the line connecting the charges. What is the magnitude of this field if the torque exerted on the dipole has magnitude 7.30×10−9 N⋅m ? Express your answer in newtons per coulomb to three significant figures.
Answer:
The magnitude of this field is 826 N/C
Explanation:
Given;
The torque exerted on the dipole, T = 7.3 x 10⁻⁹ N.m
PEsinθ = T
where;
E is the magnitude of the electric field
P is the dipole moment
First, we determine the magnitude dipole moment;
Magnitude of dipole moment = q*r
P = 4.1 x 10⁻⁹ x 3.6 x 10⁻³ = 1.476 x 10⁻¹¹ C.m
Finally, we determine the magnitude of this field;

E = 826 N/C (in three significant figures)
Therefore, the magnitude of this field is 826 N/C
Answer:
Milk
Explanation:
It can be milk and other foods similar to milk like ice cream, cheese, yogurt, etc. This is why people say milk is good for your bones cause it has calcium
Answer:
5.025 atm
Change the 2.01 to ml then cross multiply
400/1= 2010/x
210/400=5.025
Answer:
Radius of the salami = 9.9 cm
Explanation:
The formula for calculating the radius is given below:
a = v^2/r
where a represents acceleration
v represents velocity
r represents radius
As hungry mouse ran around the salami's circumference with a tangential speed of 0.17 m/s so that means velocity = 0.17 m/s.
The centripetal acceleration of the mouse = 0.29 m/s^2
putting these values in the above formula, we get
0.29 = 0.17^2 / r
After rearranging, we get,
r = 0.17^2 / 0.29
r = 0.099 m
r = 9.9 cm
so the radius of the salami = 9.9 cm