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Charra [1.4K]
3 years ago
14

Rosa records the distance that a toy car rolls and the time it takes to cover the distance. What scientific practice is this?

Physics
2 answers:
suter [353]3 years ago
8 0

collecting data...............................

Sergio039 [100]3 years ago
3 0
Rosa is conducting the scientific practice of observation.
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Wave crests in a pond are separated by 0.2m . The period of these waves is 0.2 s . What is the speed at which these waves travel
Ne4ueva [31]

1m per minute

or .5 m per 30 seconds

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a falling skydiver slows from a speed of 52 m/s to 8 m/s in 0.8 sec as the parachute opens. what is the diver's acceleration and
Cloud [144]
I found the answers here. Hope this helps you! https://1.cdn.edl.io/sJTle6yxt3qVq7jHfdHRZJ3Xogj7ps6swBO9umNcZ6PO3SMN.docx
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3 years ago
As you travel from Detroit in a certain direction, the outside temperature, T (in degrees), depends on your distance, d (in mile
Ber [7]

Answer:

a)\Delta T= 100^{\circ}C

b)\bigtriangledown T=1^{\circ}C.mile^{-1}

c)\bigtriangledown T_4=1^{\circ}C.mile^{-1}

d)\bigtriangledown T_4=1^{\circ}C.mile^{-1}

Explanation:

Given is the data of variation of temperature with respect to the distance traveled:

Temperature T as a function of distance d:

T=(d+30) ^{\circ}C...................................(1)

(a)

Total change in temperature from the start till the end of the journey:

\Delta T= T_f-T_i..............................(2)

where:

T_f= final temperature

T_i= initial temperature

∵In the start of the journey d = 0 miles & at the end of the journey d = 100 miles.

So, correspondingly we have the eq. (2) & (1) as:

\Delta T= (100+30)-(0+30)

\Delta T= 100^{\circ}C

(b)

Now, the average rate of change of the temperature, with respect to distance, from the beginning of the trip to the end of the trip be calculated as:

\bigtriangledown T=\frac{\Delta T}{\Delta d}......................(3)

where:

\Delta d= change in distance

\bigtriangledown T=change in temperature with respect to distance

putting the respective values in eq. (3)

\bigtriangledown T=\frac{100}{100}

\bigtriangledown T=1^{\circ}C.mile^{-1}

(c)

comparing the given function of the temperature with the general equation of  a straight line:

y=m.x+c

We find that we have the slope of the equation as 1 throughout the journey and therefore the rate of change in temperature with respect to distance remains constant.

\bigtriangledown T_4=1^{\circ}C.mile^{-1}

(d)

comparing the given function of the temperature with the general equation of  a straight line:

y=m.x+c

We find that we have the slope of the equation as 1 throughout the journey and therefore the rate of change in temperature with respect to distance remains constant.

\bigtriangledown T_4=1^{\circ}C.mile^{-1}

4 0
3 years ago
Starting from rest, a 88-kg firefighter slides down a fire pole. The average frictional force exerted on him by the pole has a m
Cloud [144]

Answer:h=7.22 m

Explanation:

Given

mass of firefighter m=88 kg

Frictional Force F=800 N

average speed at bottom v=3.2 m/s

Let h be the height of Pole

net force on Firefighter is

F_{net}=88\times 9.8-800=62.4

therefore net acceleration is

a_{net}=\frac{62.4}{88}=0.709 m/s^2

using v^2-u^2=2ah

here v=3.2 m/s

u=0

(3.2)^2-0=2\times 0.709\times h

h=\frac{10.24}{1.418}

h=7.22 m

3 0
3 years ago
How do catalysts speed up reactions<br><br><br><br> please help quickly
MissTica
How do catalysts speed up reactions ?
 

by reducing the amount of energy required for the reaction to occur.  other factors such as <span>catalysts' ability to speed a process are temperature, concentration </span>
8 0
3 years ago
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