Explanation:
In this reaction, the reactants are Li and N2. The product is Li3N
So we have;
Li + N2 → Li3N
Upon balancing, we have;
6Li + N2 → 2 Li3N
The sum of the coefficients is 6 + 1 + 2 = 9
Answer:
I think the answer to the question is c
Answer:
copper(ll) carbonate
Explanation:
Since the product is a salt which is copper(II) carbonate, water and carbon dioxide, this reaction is an acid + metal carbonate reaction.
Looking at the salt, Cu²⁺ has to be part of the reactants.
Hence, the missing compound there has to be copper(ll) carbonate, CuCO₃.
The balanced chemical equation would be:
CuCO₃ + 2HNO₃➙ Cu(NO₃)₂ +H₂O +CO₂
P.s. You left out CO₂ as a product in Q2 ;)
Just a recap of the main reactions you would've learnt:
1) Acid + base/ alkali ➙ salt + water
2) Acid + metal ➙ salt + hydrogen gas
3) Acid + metal carbonate ➙ salt + H₂O + CO₂
Answer:
2.10x10⁻⁹ moles of Si, 143.7 moles of CCl₄, 3.49x10²⁴ atoms
Explanation:
These is the relation:
NA (6.02x10²³) ⇒ 1 mol of particles (it can be, atoms or molecules)
This are the rule of three:
NA of atoms occupies 1 mol of Si
1.27x10¹⁵ atoms will occupy (1.27x10¹⁵ .1 ) / NA = 2.10x10⁻⁹ moles of Si
NA of molecules are contained in 1 mol of CCl₄
8.65x10²⁵ molecules are contained in (8.65x10²⁵ .1)/ NA = 143.7 moles
1 mol of Ca has NA atoms
5.80 moles of Ca will have (5.80 . NA) = 3.49x10²⁴
