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trasher [3.6K]
3 years ago
12

For an endothermic reaction, how will the value for Keq change when the temperature is increased?

Chemistry
2 answers:
Nataly [62]3 years ago
4 0
I put the answer <em>C: Keq will increase</em>, on PLATO. Hope this works for you!
Vlada [557]3 years ago
3 0

Answer:

C. Keq will increase

Explanation:

Endothermic means the reaction will <em>absorb heat</em> to occur, hence an increase in temperature will favor the reaction, increasing the formation of products.

Keq is the equilibrium constant of the reaction, and it can be defined as:

Keq = \frac{concentration of products}{concentration of reactants}

In an endothermic reaction the equilibrium will be shift towards the formation of products when the temperature is increased, the concentration of products will increase (in relation to the concentration of reactants) ; so as a result the equilibrium constant Keq will also increase.

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Complete Question

The complete question is shown on the first uploaded image

Answer:

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Splitting pattern for Hb and Hc= 3+1 , Quartet

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Splitting pattern for Hd= 0+1 , Singlet

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Explanation:

Considering the first question the rule used for prediction of splitting pattern is n+1 (Pascal's Triangle rule), where n is number of H atom on the adjacent carbon which are non equivalent.

According to that for molecule 1 as shown on the second uploaded image

For Proton Ha, number of non equivalent protons n= 2

Splitting pattern for Ha= 2+1 , Triplet

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Splitting pattern for Hb and Hc= 3+1 , Quartet

For Proton Hd, number of non equivalent protons n= 0

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Considering the second question for Molecule 2 as shown on the third uploaded image  

For Proton Ha, number of non equivalent protons n= 1

Splitting pattern for Ha= 1+1=2 , Doublet

For Proton Hb, number of non equivalent protons n= 3

Splitting pattern for Hb= 3+1=4 , Quartet

For Proton Hc, number of non equivalent protons n= 3

Splitting pattern for Hc= 3+1=4 , Quartet

For Proton Hd, number of non equivalent protons n= 1

Splitting pattern for Ha= 1+1=2 , Doublet

Considering the third question

The name of the given molecule  is gotten according to longest carbon chain  = 4 (Prefix 'Butan')

Functional group = -OH (Suffix 'ol') at C-2

The IUPAC name is Butan-2-ol

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