I'm assuming we're applying the standard Integral form of the calculation of work. The solution is provided in the image.
Answer the following questions. Use complete sentences.
1 answer:
Answer:
The motion of a projectile consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- A uniformly accelerated motion (constant acceleration, equal to the acceleration due to gravity) along the vertical direction
In terms of vectors, we have the following:
Velocity:
- The horizontal velocity does not change - therefore, this vector is constant
- The vertical velocity changes, as the vertical motion is accelerated - therefore, this vector changes. This is because there is a downward force acting on the projectile, the force of gravity.
Acceleration:
- There is no acceleration along the horizontal direction, so here the vector is zero
- The acceleration along the vertical direction is constant, and it is in the downward direction (acceleration due to gravity)
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RESULT: Twalk= 3.64 hr
Answer:
15.7 m
Explanation:
The range (horizontal distance) of the projectile is determined only by its horizontal motion.
The horizontal motion is a motion with constant speed, which is equal to the initial horizontal velocity of the object:
where
v = 12.0 m/s is the initial velocity
is the angle between the direction of v and the horizontal
Substituting,
We know that the projectile hits the ground in a time of
t = 2.08 s
so the horizontal distance covered is
Hooke's Law
k = spring constant
x = stretch
F = force
Input the value