B might be the correct answer
Answer:
457.81 Hz
Explanation:
From the question, it is stated that it is a question under Doppler effect.
As a result, we use this form
fo = (c + vo) / (c - vs) × fs
fo = observed frequency by observer =?
c = speed of sound = 332 m/s
vo = velocity of observer relative to source = 45 m/s
vs = velocity of source relative to observer = - 46 m/s ( it is taking a negative sign because the velocity of the source is in opposite direction to the observer).
fs = frequency of sound wave by source = 459 Hz
By substituting the the values to the equation, we have
fo = (332 + 45) / (332 - (-46)) × 459
fo = (377/ 332 + 46) × 459
fo = (377/ 378) × 459
fo = 0.9974 × 459
fo = 457.81 Hz
Answer:
let's say you're on a bus going 50 km/hr, you are moving at a velocity of zero relative to the bus. however, relative to the ground you are moving at the same velocity as the bus.
Explanation:
physics
A stable air mass is most likely to have POOR SURFACE VISIBILITY.
Stable air mass refers to those air mass that have marked stability in their lower layers. The characteristics of stable air mass include the following: cloud cover, smooth air, uninterrupted precipitation and low visibility.<span />
Given:
Force(F): 100 N
Acceleration: 10 m/s^2
Now we know that
F= mx a
Where F is the force acting on the object which is measured in Newton
m is the mass of the object measured in Kg
a is the acceleration measured in m/s^2
Substituting the given values in the above formula we get
100= 10m
m= 10 Kg
