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ArbitrLikvidat [17]
3 years ago
9

Use the table to answer the question.

Physics
1 answer:
e-lub [12.9K]3 years ago
4 0

Answer:

The student which is correct is Anya

Explanation:

The wavelength of a wave is the length of one complete wave cycle and it is represented by Greek letter lambda (λ)

The frequency of a wave is the number of waves (complete wave cycles) passing a given point over a given time period and the frequency is represented by the Greek letter nu (ν) and also as "f" (which is the first letter of the word "frequency")

Therefore, the speed, "v", (different from nu (ν)) of the wave is given as follows;

v = f × λ

From which we have;

λ = v/f

∴ λ ∝ 1/f

Which indicates an inversely proportional relationship between the wavelength and the frequenct

From which we have that as the wavelength decreases, the frequency increases

Therefore, Anya decrease increase is correct

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(a) when rebuilding her car's engine, a physics major must exert 300 n of force to insert a dry steel piston into a steel cylind
Vilka [71]
There are some missing data in the text of the problem. I've found them online:
a) coefficient of friction dry steel piston - steel cilinder: 0.3
b) coefficient of friction with oil in between the surfaces: 0.03

Solution:
a) The force F applied by the person (300 N) must be at least equal to the frictional force, given by:
F_f = \mu N
where \mu is the coefficient of friction, while N is the normal force. So we have:
F=\mu N
since we know that F=300 N and \mu=0.3, we can find N, the magnitude of the normal force:
N= \frac{F}{\mu}= \frac{300 N}{0.3}=1000 N

b) The problem is identical to that of the first part; however, this time the coefficienct of friction is \mu=0.03 due to the presence of the oil. Therefore, we have:
N= \frac{F}{\mu}= \frac{300 N}{0.03}=10000 N
8 0
3 years ago
Read the scenario below and answer the question that follows. Randall is hiring cooks for his restaurant. The first applicant is
Talja [164]
Randall has unconscious assumption that attractive people are more competent
4 0
3 years ago
Gravity on earth is 9.8 m/s squared, and gravity on the moon is 1.6 m/s squared. So if the mass of an object on earth is 40 kilo
garik1379 [7]

The mass of an object on Earth is the same as its mass on the Moon. The weight is different.

Weight = m * g

Weight ( Moon ) = 40 kg * 1.6 m/s² = 64 N

If the mass of an object on Earth is 40 kg, its mass on the Moon is 40 kg and its weight on the Moon is 64 N. 

7 0
3 years ago
Two polarizers A and B are aligned so that their transmission axes are vertical and horizontal, respectively. A third polarizer
Reptile [31]

Answer:

Explanation:

Let the angle between the first polariser and the second polariser axis is θ.

By using of law of Malus

(a)

Let the intensity of light coming out from the first polariser is I'

I' = I_{0}Cos^{2}\theta     .... (1)

Now the angle between the transmission axis of the second and the third polariser is 90 - θ. Let the intensity of light coming out from the third polariser is I''.

By the law of Malus

I'' = I'Cos^{2}\left ( 90-\theta \right )

So,

I'' = I_{0}Cos^{2}\theta Cos^{2}\left ( 90-\theta \right )

I'' = I_{0}Cos^{2}\theta Sin^{2}\theta

I'' = \frac{I_{0}}{4}Sin^{2}2\theta

(b)

Now differentiate with respect to θ.

I'' = \frac{I_{0}}{4}\times 2 \times 2 \times Sin2\theta \times Cos 2\theta

I'' = \frac{I_{0}}{2}\times Sin 4\theta

7 0
3 years ago
A ball is thrown vertically downward at 10 m/s. what is it’s speed 1s and 2s later
soldi70 [24.7K]

Answer:

20 m/s

30 m/s

Explanation:

Given:

v₀ = -10 m/s

a = -9.8 m/s²

When t = 1 s:

v = v₀ + at

v = (-10 m/s) + (-9.8 m/s²) (1 s)

v = -19.8 m/s

When t = 2 s:

v = v₀ + at

v = (-10 m/s) + (-9.8 m/s²) (2 s)

v = -29.6 m/s

Rounded to one significant figures, the speed of the ball at 1 s and 2 s is 20 m/s and 30 m/s, respectively.

3 0
3 years ago
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