Answer:
Explanation:
A novae in astronomy means an explosion in the white dwarf star which had tapped enough gas from a companion star,hence it releases an incredible amount of energy which is Over a million times brighter than it normal stars.
A super novae on the other hand is a cosmic explosion that can be a billion times brighter than the normal.
From this one can see that a perculiar similarity between a novae and super novae is that both generate huge explosion and bright Ness, and a major difference is super novae release huge amount of brightness and energy more than the novae
Answer:
The options are not shown, so i will answer in a general way.
Suppose the case where the forces act in opposite directions, then we need to subtract the forces, and we know that the magnitude of the resultant force will be:
60N - 50N = 10N
Now, suppose the case where both forces act in the exact same direction, in that case, we will add the forces to get:
60N + 50N = 110N
Then the only range of forces that we can get in this system, are the forces such:
10N ≤ F ≤ 110N
Any resultant force outside that range is not possible in this situation.
Answer:
Clockwise and counter clockwises, depands.
Explanation:
The direction of current in a loop of wire in a magnatic field depands on the direction in which the loop is moved and the applied magnatic field.
this is determined by what is called right hand rule.
I will give one scenario, let's say that the loop is moved upwards and the applied magnatic field is into the page (if you drew the loop in 2D on a piece of paper), in this case the direction would be clockwise.
Answer:
v_f =63 m/s
Explanation:
given,
starting force = 0 N
uniform rate increase to 36 N
time of action of Force = 35 s
mass of the body = 10 Kg
Speed of the object = ?
From the given data
if we plot F-t curve we will get a triangular shape
we know,
Impulse = Area between F-t curve
= (1/2) x base x height
= 0.5 x 35 x 36
= 630 N.s
now use Impulse-momentum theorem
Impulse = change in momentum
630 = 10 x (v_f - vi)
630 = 10 x (v_f - 0)
v_f =63 m/s
Speed of the object at 35 sec is equal to v_f =63 m/s
