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koban [17]
3 years ago
10

Which equation represents the total energy of a system?

Physics
1 answer:
suter [353]3 years ago
3 0
Initial Energy+Work=Final Energy
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Read the passage.
Paladinen [302]
<h2>Answer: B)Scientists’ understanding of cells continually improved as the results of studies built upon each other over time and formed the cell theory.</h2>

Explanation:

Nowadays we know <u>cells are essential microscopic units that make up the living beings, capable of reproducing independently. </u>

However, this is the result of a long process of discoveries and studies made since the 19th century, in which the continuous improvement of new technologies was helpful.

In fact, it is wel known the English scientist Robert Hooke was the first to discover the existence of cells by looking through a compound microscope at a cork sheet, realizing that it was made up of small polygonal holes (like those of a honeycomb) that reminded him of the chambers in which the monks stayed (called cells). Then, during the next centuries more studies were made until we had the current knowledge about the structure of a cell.

7 0
3 years ago
A burglar attempts to drag a 108 kg metal safe across a polished wood floor Assume that the coefficient of static friction is 0.
V125BC [204]

Answer:

2.00 m/s²

Explanation:

Given

The Mass of the metal safe, M = 108kg

Pushing force applied by the burglar,  F = 534 N

Co-efficient of kinetic friction, \mu_k = 0.3

Now,

The force against the kinetic friction is given as:

f = \mu_k N = u_k Mg

Where,

N = Normal reaction

g= acceleration due to the gravity

Substituting the values in the above equation, we get

f = 0.3\times108\times9.8

or

f = 317.52N

Now, the net force on to the metal safe is

F_{Net}= F-f

Substituting the values in the equation we get

 F_{Net}= 534N-317.52N

or

F_{Net}= 216.48

also,

 

F_{Net}= M\timesacceleration of the safe

Therefore, the acceleration of the metal safe will be

acceleration of the safe=\frac{F_{Net}}{M}

or

 acceleration of the safe=\frac{216.48}{108}

or

 

acceleration of the safe=2.00 m/s^2

Hence, the acceleration of the metal safe will be  2.00 m/s²

3 0
3 years ago
An airplane flies 1,592 miles east from Phoenix, Arizona, to Atlanta, Georgia, in 3.68 hours.
Gnoma [55]
Maybe it is around 300
8 0
3 years ago
A cart moving at 10 m/s is brought to a stop by the force plotted in the force-time graph shown here. Find the impulse and the a
Elena L [17]

Answer:

Impulse = 88 kg m/s

Mass = 8.8 kg

Explanation:

<u>We are given a graph of Force vs. Time. Looking at the graph we can see that the Force acts approximately between the time interval from 1sec to 4sec. </u>

Newton's Second Law relates an object's acceleration as a function of both the object's mass and the applied net force on the object. It is expressed as:

F=ma      Eqn. (1)

where

F : is the Net Force in Newtons ( N )

m : is the mass ( kg )

a  : is the acceleration ( m/s^2 )

We also know that the acceleration is denoted by the velocity ( v ) of an object as a function of time ( t ) with

a=\frac{v}{t}         Eqn. (2)

Now substituting Eqn. (2) into Eqn. (1) we have

F=m\frac{v}{t}\\ \\Ft=mv     Eqn. (3)

However since in Eqn. (3) the time-variable is present, as a result the left hand side (i.e. Ft is in fact the Impulse  J of the cart ), whilst the right hand side denotes the change in momentum of the cart, which by definition gives as the impulse. Also from the graph we can say that the Net Force is approximately ≈ 22N and t=4 sec (thus just before the cut-off time of the force acting).

Thus to find the Impulse we have:

J=Ft\\J=(22N)(4sec)\\J=88 kg m/s

So the impulse of the cart is J=88kg m/s

Then, we know that the cart is moving at v=10 m/s. Plugging in the values in Eqn. (3) we have:

(22N)(4sec)=(10m/s)m\\\\88=10m\\\\m=\frac{88}{10}\\ \\m=8.8kg

So the mass of the cart is m=8.8kg.

8 0
4 years ago
What is the direction of the magnetic field b⃗ a at point a?
Nitella [24]
I need to see the diagram
8 0
3 years ago
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