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koban [17]
3 years ago
10

Which equation represents the total energy of a system?

Physics
1 answer:
suter [353]3 years ago
3 0
Initial Energy+Work=Final Energy
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Unemployment cause stress which ultimately has long-term physiological health effect

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A square coil, enclosing an area with sides 2.0 cm long, is wrapped with 2 500 turns of wire. A uniform magnetic field perpendic
Delvig [45]

Answer:

The induced voltage in the coil is 0.25 V.

Explanation:

It is given that,

Area of a square coil is 2 cm or 0.02 m

Number of turns in the wire is 2500

A uniform magnetic field perpendicular to its plane is turned on and increases to 0.25 T during an interval of 1.0 s.

We need to find the induced voltage in the coil. According to Faraday's law, the induced emf in the coil is given by the rate of change on magnetic flux. So,

\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(NBA)}{dt}\\\\\epsilon=NA\dfrac{-dB}{dt}\\\\\epsilon=-2500\times (0.02)^2\times \dfrac{0.25}{1}\\\\\epsilon=-0.25\ V

So, the induced voltage in the coil is 0.25 V.

3 0
3 years ago
A 0.50-kg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.9 m on a frictionless horizontal su
Sedaia [141]

Answer:

\boxed {\boxed {\sf 18 \ m/s}}

Explanation:

The ball is moving in a circle, so the force is centripetal.

One formula for calculating centripetal force is:

F_c= \frac{mv^2}r}

The mass of the ball is 0.5 kilograms. The radius is 1.9 meters. The centripetal force is 85 Newtons or 85 kg*m/s².

  • F_c= 85 kg*m/s²
  • m= 0.5 kg
  • r= 1.9 m

Substitute the values into the formula.

85 \ kg*m/s^2 = \frac{0.5 \ kg *v^2}{1.9 \ m}

Isolate the variable v. First, multiply both sides by 1.9 meters.

(1.9 \ m)(85 \ kg*m/s^2) = \frac{0.5 \ kg *v^2}{1.9 \ m}*1.9 \ m

(1.9 \ m)(85 \ kg*m/s^2) = {0.5 \ kg *v^2}

161.5 \ kg*m^2/s^2 = 0.5 \ kg*v^2

Divide both sides by 0.5 kilograms.

\frac {161.5 \ kg*m^2/s^2}{0.5 \ kg} = \frac{0.5 \ kg*v^2}{0.5 \ kg}

\frac {161.5 \ kg*m^2/s^2}{0.5 \ kg} =v^2

323 \ m^2/s^2 = v^2

Take the square root of both sides of the equation.

\sqrt {323 \ m^2/s^2} =\sqrt{ v^2

\sqrt {323 \ m^2/s^2} =v

17.9722007556 \ m/s =v

The original measurements have 2 significant figures, so our answer must have the same.

For the number we found, 2 sig fig is the ones place. The 9 in the tenth place tells us to round the 7 to an 8.

18 \ m/s =v

The maximum speed is approximately <u>18 meters per second.</u>

8 0
3 years ago
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