Question

A heat release of 4800 J for 8 minutes is released in the conductor during the flow of electricity. What is the current in the conductor? The conductor resistance is 1kΩ​

Answer 1

Answer: 0.1 Amps

Explanation:

Given that,

heat released (H) = 4800 J

Time taken (T) = 8 minutes

Since the unit of time is seconds, convert 8 minutes to seconds

(1 minute = 60 seconds

8 minutes = 8 x 60 = 480 seconds)

current in the conductor (I) = ?

The conductor resistance (R) = 1kΩ​

Convert kilo-Ohms (kΩ​) to ohms (Ω​)

(If 1000Ω = 1kΩ

1kΩ = 1000Ω)

Now, apply the formula:

H = I²RT

4800J = I² x 1000Ω x 480 Seconds

4800J = 480000Ω•I²

Divide both sides by 480000Ω

4800J/480000Ω = 480000Ω•I²/ 480000Ω

0.01 = I²

To get the value of I, find the square root of I²

I = √0.01

I = 0.1 Amps

Thus, the current in the conductor is 0.1 Amps