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Molodets [167]
3 years ago
8

A heat release of 4800 J for 8 minutes is released in the conductor during the flow of electricity. What is the current in the c

onductor? The conductor resistance is 1kΩ​
Physics
1 answer:
hram777 [196]3 years ago
7 0

Answer: 0.1 Amps

Explanation:

Given that,

heat released (H) = 4800 J

Time taken (T) = 8 minutes

Since the unit of time is seconds, convert 8 minutes to seconds

(1 minute = 60 seconds

8 minutes = 8 x 60 = 480 seconds)

current in the conductor (I) = ?

The conductor resistance (R) = 1kΩ​

Convert kilo-Ohms (kΩ​) to ohms (Ω​)

(If 1000Ω = 1kΩ

1kΩ = 1000Ω)

Now, apply the formula:

H = I²RT

4800J = I² x 1000Ω x 480 Seconds

4800J = 480000Ω•I²

Divide both sides by 480000Ω

4800J/480000Ω = 480000Ω•I²/ 480000Ω

0.01 = I²

To get the value of I, find the square root of I²

I = √0.01

I = 0.1 Amps

Thus, the current in the conductor is 0.1 Amps

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What is the velocity of the object?
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<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2><h2 /><h2>\huge\boxed{\text{V = 9.5 m/s}}</h2><h2>_____________________________________</h2>

<h2>DATA:</h2>

mass = m = 2kg

Distance = x = 6m

Force = 30N

TO FIND:

Work = W = ?

Velocity = V = ?

<h2>SOLUTION:</h2>

According to the object of mass 2 kg travels a distance when the force was exerted on it. The graph between the Force and position was plotted which shows that 30 N of force was used to push the object till the distance of 6.0m.

To find the work, I will use the method of determining the area of the plotted graph. As the graph is plotted in the straight line between the Force and work, THE PICTURE ATTCHED SHOWS THE AREA COVERED IN BLUE AS WORK DONE AND HEIGHT AS 30m AND DISTANCE COVERED AS 6m To solve for the area(work) of triangle is given as,

{\Longrightarrow}\qquad \qquad \qquad W\ =\ \frac{1}{2}\;(Base)\:(Height)

Base is the x-axis of the graph which is Position i.e. 6m

Height is the y-axis of the graph which is Force i.e. 30N

So,

                           W\ =\ \frac{1}{2}\:6\:x\:30

                           W   =  90 J

The work done is 90 J.

According to the principle of work and kinetic energy (also known as the work-energy theorem) states that the work done by the sum of all forces acting on a particle equals the change in the kinetic energy of the particle.

{\Longrightarrow}\qquad \qquad \qquad W\quad =\quad K.E\\\\{\Longrightarrow}\qquad \qquad \qquad W\quad =\quad \frac{1}{2}\ m\ V^2 \\\\{\Longrightarrow}\qquad \qquad \qquad W\quad =\quad \frac{1}{2}\ 2\ (V_f-V_i)^2\\\\{V_i\ is\ 0\ because\ the\ object\ was\ initially\ at\ rest}\\\\ {\Longrightarrow}\qquad \qquad \qquad W\quad\ =\ \frac{1}{2}\ x\ 2\ (V_f-0)^2 \\\\{\Longrightarrow}\qquad \qquad \qquad 90\quad = \frac{1}{2}\ x\ 2\ (V_f)^2

\\\\{\Longrightarrow}\qquad \qquad \qquad V_f\quad =\ \sqrt{\frac{2\ (90)\ }{2}}\\\\{\Longrightarrow}\qquad \qquad \qquad \boxed {V_f\quad =\ 9.48\ m/s}

\boxed{The\ Velocity\ of\ the\ Object\ of\ mass\ 2kg\ at\ 6\ meters\ of\ distance\ was\ 9.48\ m/s}

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>

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