1 cubic cm is the same as 1 mL, so the answer would be C.
Answer A is incorrect
A crest is just one point. It is not the distance between 2 crests.
B is incorrect
A trough is just 1 point. It is not the distance between 2 troughs.
C is incorrect.
the amplitude measures the height of a crest from the middle of the wave to the crest (or trough).
D is the correct answer. That is the distance between 2 crests or 2 troughs
Answer:
0.010 m
Explanation:
So the equation for a pendulum period is:
where L is the length of the pendulum. In this case I'll use the approximation of pi as 3.14, and g=9.8 m\s. So given that it oscillates once every 1.99 seconds. you have the equation:
![1.99 s = 2(3.14)\sqrt{\frac{L}{9.8 m\backslash s^2}}\\](https://tex.z-dn.net/?f=1.99%20s%20%3D%202%283.14%29%5Csqrt%7B%5Cfrac%7BL%7D%7B9.8%20m%5Cbackslash%20s%5E2%7D%7D%5C%5C)
Evaluate the multiplication in front
![1.99 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}](https://tex.z-dn.net/?f=1.99%20s%20%3D%206.28%5Csqrt%7B%5Cfrac%7BL%7D%7B9.8m%5Cbackslash%20s%5E2%7D)
Divide both sides by 6.28
![0.317 s= \sqrt{\frac{L}{9.8 m\backslash s^2}}](https://tex.z-dn.net/?f=0.317%20s%3D%20%5Csqrt%7B%5Cfrac%7BL%7D%7B9.8%20m%5Cbackslash%20s%5E2%7D%7D)
Square both sides
![0.100 s^2= \frac{L}{9.8 m\backslash s^2}](https://tex.z-dn.net/?f=0.100%20s%5E2%3D%20%5Cfrac%7BL%7D%7B9.8%20m%5Cbackslash%20s%5E2%7D)
Multiply both sides by m/s^2 (the s^2 will cancel out)
Now now let's find the length when it's two seconds
![2.00 s = 6.28\sqrt{\frac{L}{9.8m\backslash s^2}}](https://tex.z-dn.net/?f=2.00%20s%20%3D%206.28%5Csqrt%7B%5Cfrac%7BL%7D%7B9.8m%5Cbackslash%20s%5E2%7D%7D)
Divide both sides by 6.28
![0.318 s = \sqrt{\frac{L}{9.8 m\backslash s^2}](https://tex.z-dn.net/?f=0.318%20s%20%3D%20%5Csqrt%7B%5Cfrac%7BL%7D%7B9.8%20m%5Cbackslash%20s%5E2%7D)
Square both sides
![0.101 s^2 = \frac{L}{9.8 m\backslash s^2}](https://tex.z-dn.net/?f=0.101%20s%5E2%20%3D%20%5Cfrac%7BL%7D%7B9.8%20m%5Cbackslash%20s%5E2%7D)
Multiply both sides by 9.8 m/s^2 (s^2 will cancel out)
![0.994 m = L](https://tex.z-dn.net/?f=0.994%20m%20%3D%20L)
So to find the difference you simply subtract
0.984 - 0.994 = 0.010 m