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pav-90 [236]
3 years ago
9

Doppler Effect: A stationary source produces a sound wave at a frequency of 50 Hz. The wave travels at 100 feet per second. A ca

r is moving toward the sound source at a speed of 100 feet per second. What is the wavelength of the stationary sound source and the wave length that a person in the car perceives?
(Show the formulas and your calculations)

THANK YOU
Physics
1 answer:
Leno4ka [110]3 years ago
6 0

Answer:

︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎

︎

︎ ︎ ︎︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎

︎

︎ ︎ ︎︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎ ︎

Explanation:

Hope it helps!

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Two truckers are traveling directly away from each other at the same speed. If one trucker sounds her horn at a frequency of 221
8_murik_8 [283]

Answer:

v = 8.8 m /s

Explanation:

For listener and source going away from each other the formula of Doppler effect is as follows

\frac{f}{f_0} = \frac{V-v}{V+v}

V is velocity of sound , v is velocity of listner and source of sound

f₀ is apparent frequency and f is real frequency

V = 343 , v = ? ,f = 210 , f₀ = 221

Put these value in the relation above

[tex]\frac{210}{221} = \frac{343-v}{343+v}[/tex]

v = 8.8 m /s

6 0
3 years ago
A car is traveling on a straight, level road under wintry conditions. Seeing a patch of ice ahead of her, the driver of the car
dangina [55]
Her magnitude of deceleration on the ice would be 15.126m/s
5 0
3 years ago
An investigator places a sample 1.0 cm from a wire carrying a large current; the strength of the magnetic field has a particular
AURORKA [14]

Answer:

she must increase the current by factor of 7

Explanation:

The magnetic field produced by a steady current flowing in a very long straight wire encircles the wire.In order to solve the question, we use this formula,

B= μo I/(2πr)

where,

'μo'  represents permeability of free space i.e 4π*10-7 N/A2

B=magnetic field

I= current

r=radius

->When r= 1cm=> 0.01m

B1 = μo I_{1/(2π x 0.01)

->when r=7cm =>0.07m

B2 = μo I_{2}/(2π x 0.07)

Now equating both of the magnetic fields, we have

B1= B2

μo I_{1/(2π x 0.01)= μo I_{2}/(2π x 0.07)

I_{1/  I_{2}= 0.01/0.07

I_{1/  I_{2}= 1/ 7

Therefore, she must increase the current by factor of 7

5 0
3 years ago
5. the combustion of a single molecule of methane produces about 10 ev of energy. a methane molecule has a mass of 16 amu. the f
Alchen [17]

The mass of methane will produce as much energy as a single gram of uranium-235 1,287 kilograms of methane. Option D is correct.

<h3>What is uranium?</h3>

Uranium, with the atomic number 92 and the symbol U in the periodic table, is a weakly radioactive element. One of the heavy metals that may be used as a concentrated energy source is uranium.

Given data;

⇒One mole of U-235 = 235 grams

=> 1 gram of U-235 = 1/235 moles

⇒1 mole of U-235 = 6.023 x 10²³ atoms

The no of atoms is;

=> 1/235 moles of U-235

⇒N = 6.023 x 10²³/235 atoms

⇒N=25.6 x 10²⁰ atoms

If one atom of U-235 gives is 189 x 10⁶ eV energy,25.6 x 10²⁰ atoms of U-235 gives;

=> 25.6 x 10²⁰ atoms of U-235 gives;

E = 25.6 x 10²⁰ x 189 x 10⁶

E= 4.8 x 10²⁹ eV energy

One methane molecule produces;

E = 10 eV of energy

=> To produce 4.8 x 10²⁹ eV energy, no. of molecules required;

= 4.8 x 10²⁸

6.032 x 10²³ molecules of methane = 16 gms

=> 4.8 x 10²⁸ molecules of methane = 16 x 4.8 x 10²⁸/ 6.032 x 10²³ gms

m= 12.75 x 10⁵ gms

m= 1275 kilograms of methane

m≅ 1287 kilograms of methane

1 gram of U-235 has the same amount of energy as 1287 kilograms of methane.

Hence option D is correct,

To learn more about uranium refer to the link;

brainly.com/question/9099776

#SPJ1

7 0
2 years ago
Which of the following is not something that the atmosphere does for us?
Masja [62]
Tha atmosphere has no effect on gravity.
4 0
3 years ago
Read 2 more answers
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