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2 years ago

Soapy water between surfaces

Physics

2 answers:

alisha [4.7K]2 years ago

8 0

Answer:

C. reduces friction

Explanation:

Soapy water between surfaces reduces friction.

Inessa [10]2 years ago

6 0

Answer:

A.increases friction

Explanation:

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An Olympic diver springs off of a high dive that is 3 m above the surface of the water. When she lands in the water she is trave

klemol [59]

Answer: $u=4.51 m/s\ at\ angle\ of\ \theta =59.34^{\circ}$

Explanation:

Given

height of building h=3 m

Landing velocity of diver $v=8.90 m/s$ at an angle of $75^{\circ}$

Let u be the initial velocity of diver at an angle of \theta with horizontal

Since there is no acceleration in horizontal direction therefore horizontal component of velocity will remain same

$u\cos \theta =8.9\cos (75)$ ---- -----1

Considering Vertical motion

$v^2-u^2=2as$

here $v=8.9\sin (75)$

$u=u\sin \theta$

$s=3 m$

$a=9.8 m/s^2$

$(8.9\sin (75))^2-(u\sin \theta )^2=2\times 9.8\times 3$

$u\sin \theta =\sqrt{(8.9\sin 75)^2-(2\cdot 9.8\cdot 3)}$

$u\sin \theta =3.886$ ----------------2

Divide 2 and 1 we get

$\tan \theta =\frac{3.886}{8.9\cos (75)}$

$\tan \theta =1.687$

$\theta =59.34^{\circ}$

Thus $u\cos (59.34)=8.9\cos (75)$

$u=4.51 m/s$

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Point charge A is located at point A and point charge B is at point B. Points A and B are separated by a distance r. To determin

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Answer:

B. The algebraic sum of the two electric potentials is determined at a distance r/2 from each of the charges, making sure to include the signs of the charges.

Explanation:

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The answer for this question is b, Lamarck!

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If two firecrackers produce a sound level 85dB. What level does the explosion of one firecracker produce?

mars1129 [50]

Level of sound is related to intensity by this equation

$L = 10 Log \frac{I}{I_o}$

given that

L = 85 dB

also we know that

$I_o = 10^{-12} W/m^2$

now we have

$85 = 10 Log \frac{I}{10^{-12}}$

By solving above equation

$I = 10^{8.5} * 10^{-12}$

$I = 3.16 * 10^{-4} W/m^2$

now above is the intensity due to two firecrackers and if we wish to find the sound level of one firecracker then we will find its half level intensity

$I_1 = \frac{I}{2}$