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Lemur [1.5K]
3 years ago
6

In order to sail through the frozen Arctic Ocean, the most powerful icebreaker ever built was constructed in the former Soviet U

nion. At the heart of the ship’s power plant is a nuclear reactor with a power output of 5.60* 10^7 W. How long will it take for this power plant to do 5.35* 10^10 J of work?
Physics
1 answer:
professor190 [17]3 years ago
6 0

Answer:

955.36 seconds ≈ 16 minutes

Explanation:

Power(P) is the rate of doing work(W)

That is, P = W/t, where t is the time.

multipying both sides with 't' and dividing with 'P', we get: t=W/P

Here, W = 5.35 x 10^10 J and P = 5.6 x 10^7 W ( 1 W = 1 J/s).

Therefore , on dividing W with P, we get 955.36 seconds.

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Explanation:

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Why is this event important to include in the biography?
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Answer:

D: It shows that Frida Kahlo used art to cope with her pain.

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If you run at an average speed of 10mi/h how long will it take for you to run 2.5miles
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3 0
2 years ago
The mass luminosity relation L  M 3.5 describes the mathematical relationship between luminosity and mass for main sequence sta
ivanzaharov [21]

Answer:

(a) <u>11.3 L</u>

(b) <u>10 M</u>

Explanation:

The mass-luminosity relationship states that:

Luminosity ∝ Mass^3.5

Luminosity = (Constant)(Mass)^3.5

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Luminosity of a star/L = (Mass of Star/M)^3.5 ______ eqn(1)

where,

L = Luminosity of Sun

M = mass of Sun

(a)

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Mass of Star = 2M

Therefore, eqn (1) implies that:

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(b)

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Luminosity of star = 3160 L

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3160L/L = (Mass of Star/M)^3.5

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3 years ago
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