Answer:
The high-beam filament has more resistance than low beam filament.
Explanation:
To determine if the 50 W dissipated by a car’s headlights on high beam, has more or less resistance, formula for power dissipated in the filament is used.
Power = IV
Voltage =IR
∴ Power = I*IR = I²R
where;
I is the current
V is the voltage
R is the resistance
From the equation above, Power dissipated is directly proportional to Resistance.
Hence, the high-beam filament has more resistance than low beam filament.
Answer:
The horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g.
Explanation:
This is because, the projectile has both vertical and horizontal components of velocity. But, its vertical component of velocity changes as the object moves whereas, its horizontal component of velocity remains constant.
Also, the projectile has only vertical component of acceleration and no horizontal component of acceleration since, its horizontal component of velocity remains constant. Thus, no change in the horizontal component of velocity.
The vertical component of acceleration is equal to -g since, the weight is the only vertical force acting on it.
So, <u>the horizontal component of its velocity remains constant and the vertical component of its acceleration is equal to -g.</u>
Answer:
W of the person in moon ≈ 124.70 N
Explanation:
Weight: Weight of a body can be defined as the product of mass and the gravitational acceleration of the body. The S.I unit of weight is Newton (N). It can be expressed mathematically as
W = mg
Where W = weight of the body, m = mass of the body (kg) and a = acceleration of the body (m/s²)
Weight(W) = Mass (m) × Acceleration due to gravity (g)
∴ W = m × g.
If the person is on the moon,
Mass = 76.5 kg.
g (moon) = 16.6% of g ( earth)
But g(earth) = 9.80 m/s².
∴ g (moon) = 9.80 × (16.6/100)
g (moon) = 1.63 m/s², m = 76.5 Kg
∴ Weight of the person in moon = 76.5 × 1.63 =124.695 N
W of the person in moon ≈ 124.70 N
Answer:2t
Explanation:
Given
Jason throwing watermelon at speed v and it spend t time in air
time to reach max height
0=v-gt'
and time to reach bottom is also t'
t=2t'
For guy throws his watermelon at speed 2v
So total time in air will be
t''=2t
