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viva [34]
3 years ago
14

A 17-mm-wide diffraction grating has rulings of 530 lines per millimeter. White light is incident normally on the grating. What

is the longest wavelength that forms an intensity maximum in the fifth order
Physics
1 answer:
Sedbober [7]3 years ago
7 0

Answer:

377 nm

Explanation:

Number of lines per meter is, N &=530 \times 1000 \\ &=530000 \text { lines } / \mathrm{m} \end{aligned}

Grating element is, d=\frac{1}{N}

=1.8868 \times 10^{-6} \mathrm{~m}[tex]
Order is, n=5
Condition for maximum intensity is, [tex]d \sin \theta=n \lambda

 \lambda &=\frac{1.8868 \times 10^{-6}}{5(\sin 90)} \\
&=0.377 \times 10^{-6} \mathrm{~m} \\
&=377 \mathrm{~nm}

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Neglecting air​ resistance, the distance s left parenthesis t right parenthesis in feet traveled by a freely falling object is g
ivann1987 [24]

Explanation:

It is given that, the height of a certain tower is 862 feet i.e to reach on the ground the object should travel, s = 862 feet

The distance traveled by a freely falling object is given by :

s(t)=16t^2

16t^2=862

t=\sqrt{53.875}

t = 7.34 seconds

So, the object will take 7.34 seconds to fall to the ground from the top of the​ building. Hence, this is the required solution.

7 0
3 years ago
41
ASHA 777 [7]

Answer:

16

Explanation:

6+10=16

the box will go forward but it will be a little harder.

6 0
3 years ago
Why do we never notice quantization?
jarptica [38.1K]

Answer:

B

Explanation:

quantization of energy is only seen in atoms

7 0
3 years ago
A sling is used to give a stone an initial velocity of 20 at an angle of 30 above the horizontal. The stone travels through the
Luba_88 [7]

Answer:

Option E is correct.

There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.

Explanation:

Normally, ignoring air resistance, for projectile motion, the range (horizontal distance teavelled) of the motion is given as

R = (u² sin 2θ)/g

where

u = initial velocity of the projectile = 20 m/s

θ = angle above the horizontal at which the projectile was launched = 30°

g = acceleration due to gravity = 9.8 m/s²

R = (30² sin 60°) ÷ 9.8

R = 78.53 m

So, Normally, the stone should travel a horizontal distance of 78.53 m. So, travelling a horizontal distance of 32 m (less than half of what the range should be without air resistance) means that, the motion of the stone was impeded, hence, option E is correct.

There must be a horizontal wind opposite the direction of the stone's motion, because ignoring air resistance when calculating the horizontal range would yield a value greater than 32 m.

Hope this Helps!!!

7 0
3 years ago
A small branch is wedged under a 200 kg rock and rests on a smaller object. The small object that creates a pivot point is calle
KiRa [710]

Answer:

F = 326.7 N

Explanation:

given data

mass m = 200 kg

distance d = 2 m

length L = 12 m

solution

we know force exerted by the weight of the rock that is

W = m × g   ..............1

W = 200 × 9.8

W = 1960 N

and

equilibrium the sum  of the moment about that is

∑Mf = F(cos∅) L - W (cos∅) d  = 0

here ∅ is very small so cos∅ L = L and cos∅ d = D

so F × L - W × d = 0       .................2

put here value

F × 12 - 1960 × 2 = 0

solve it we get

F = 326.7 N

8 0
3 years ago
Read 2 more answers
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