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sertanlavr [38]
1 year ago
15

how many monochloro substitution products are produced when the alkanes below are chlorinated? consider constitutional isomers o

nly, ignore stereoisomers.
Chemistry
1 answer:
Airida [17]1 year ago
5 0

When the alkanes below are chlorinated they produce 3 monochloro substitution products. These isomers have the same chemical formula, but their atoms arrangements are different.

What are constitutional versus isomeric isomers?

Although structural (constitutional) isomers share the same chemical formula but their atoms are bonded in a different way. Stereoisomers have the same atomic configurations and chemical formulae. The groups' spatial orientation is the only thing which distinguishes the molecules distinguishes them from one another.

What are instances of stereoisomers?

According to the general definition of stereoisomers, stereoisomers are isomers with the same composition (i.e., the same parts), but different orientations in space. Stereoisomers are of two different types which are enantiomers and diastereomers.

Learn more about stereoisomers from the link given below.

brainly.com/question/13839157

#SPJ4

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Complete the dissociation reaction and the corresponding Ka equilibrium expression for each of the following acids in water. (Ty
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HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)

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K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}

(B) The dissociation reaction of Co(H_2O)_6^{3+} will be:

Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)

The equilibrium expression :

K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}

(C) The dissociation reaction of CH_3NH_3^+ will be:

CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)

The equilibrium expression :

K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

(A) The dissociation reaction of HC_2H_3O_2 will be:

HC_2H_3O_2(aq)\rightleftharpoons H^+(aq)+C_2H_3O_2^-(aq)

The equilibrium expression of HC_2H_3O_2 will be:

K_a=\frac{[H^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}

(B) The dissociation reaction of Co(H_2O)_6^{3+} will be:

Co(H_2O)_6^{3+}(aq)\rightleftharpoons H^+(aq)+Co(H_2O)_5(OH)^{2+}(aq)

The equilibrium expression of Co(H_2O)_6^{3+} will be:

K_a=\frac{[H^+][Co(H_2O)_5(OH)^{2+}]}{[Co(H_2O)_6^{3+}]}

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CH_3NH_3^+(aq)\rightleftharpoons H^+(aq)+CH_3NH_2(aq)

The equilibrium expression of CH_3NH_3^+ will be:

K_a=\frac{[H^+][CH_3NH_2]}{[CH_3NH_3^+]}

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