<span>1 Cu + 2 H</span>₂<span>SO</span>₄<span> = 1 CuSO</span>₄<span> + 2 H</span>₂<span>O + 1 SO</span>₂
Coefficient od CuSO₄ = 1
hope this helps!
I this is really hard who can help me complete all of these because this is acknowledged
Answer:
9.4
Explanation:
The equation for the reaction can be represented as:
+
⇄ 
The ICE table can be represented as:
+
⇄ 
Initial 0.27 0.49 0.0
Change -x -2x x
Equilibrium 0.27 - x 0.49 -2x x
We can now say that the concentration of
at equilibrium is x;
Let's not forget that at equilibrium
= 0.11 M
So:
x = [
] = 0.11 M
[
] = 0.27 - x
[
] = 0.27 - 0.11
[
] = 0.16 M
[
] = (0.49 - 2x)
[
] = (0.49 - 2(0.11))
[
] = 0.49 - 0.22
[
] = 0.27 M
![K_C = \frac{[CH_3OH]}{[CO][H_2]^2}](https://tex.z-dn.net/?f=K_C%20%3D%20%5Cfrac%7B%5BCH_3OH%5D%7D%7B%5BCO%5D%5BH_2%5D%5E2%7D)


= 9.4
∴ The equilibrium constant at that temperature = 9.4
No. of atoms=mols*avagadros no.
N=n*No
N=17 * 6.022 *10^23
No. Of atoms=(17) (6.022*10^23)
A theory does not change into a scientific law with the accumulation of new or better evidence. A theory will always remain a theory