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spin [16.1K]
3 years ago
5

The Olympic record for running the 200 m dash is 19.3 seconds. What is the average speed for this record?

Physics
2 answers:
Hoochie [10]3 years ago
8 0

Answer:

A

Explanation:

v = change of X / change of T

v = 200/19.3

g100num [7]3 years ago
3 0

Answer:

A. 10.36 m/s

Explanation:

The Olympic record for running the 200 m dash is 19.3 seconds. What is the average speed for this record?

A. 10.36 m/s

B. 3960 m/s

C. 219.3 m

D. 0.0965 m/s

speed is the change in distance per time

speed is scalar quantity and hence as no direction but only magnitude. time  and distance are also  scalar quantity

200/19.3

speed=10.36m/s

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8)
Pachacha [2.7K]

Answer: The answer would be 10

Explanation:

7 0
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How far (in meters) will you travel in 3 minutes running at a rate of m/s?
Daniel [21]
10 minutes I don’t know id this is right
3 0
3 years ago
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A ball rolls 50 meters in
-Dominant- [34]

The speed of the ball is B. 5 meters per second

Explanation:

For an object in uniform motion (= at constant velocity), the speed can be calculated using the equation

v=\frac{d}{t}

where

v is the speed

d is the distance covered

t is the time taken

For the ball in this problem:

d = 50 m is the distance covered

t = 10 s is the time taken

Substituting, we find the speed:

v=\frac{50}{10}=5 m/s

Learn more about speed:

brainly.com/question/8893949

#LearnwithBrainly

3 0
3 years ago
Dario, a prep cook at an Italian restaurant, spins a salad spinner and observes that it rotates 20.0 times in 5.00 seconds and t
BabaBlast [244]

Answer:

-\frac{8\pi}{3}rad/s^2

Explanation:

To solve this problem we need to apply the concept related to Angular Acceleration. We can find it through the equation

\omega_f^2-\omega_i^2=2\alpha\theta

Where for definition,

\omega_i = \frac{\theta}{t}

The number of revolution (\theta)was given by 20 times, then

\omega_i = \frac{20*2pi}{5}

\omega = 8\pi rad/s

We know as well that the salad rotates 6 more times, therefore in angle measurements that is

\theta = 6*2\pi rad = 12\pi rad

The cook at the end stop to spin, then using our first equation,

0-8\pi = 2\alpha (12\pi)

re-arrange to solve\alpha ,

\alpha = \frac{-8\pi}{2*12\pi}

\alpha = -\frac{8\pi}{3}rad/s^2

We can know find the required time,

\omega_f-\omega_i = \alpha t

Re-arrange to find t, and considering that \omega_f=0

t= \frac{\omega_i}{\alpha}

t=\frac{-8\pi}{-8\pi/3}

t=3s

Therefore take for the salad spinner to come to rest is 3 seconds with acceleration of -\frac{8\pi}{3}rad/s^2

6 0
3 years ago
Read 2 more answers
. (Serway 9th ed., 7-33) A 0.600-kg particle has a speed of 2.00 m/s at point A and a kinetic energy of 7.50 J at point B. What
k0ka [10]

Answer:

a) KA = 1.2 J

b) vB = 5.00 m/s

c) W = 6.30 J

Explanation:

m = 0.600 kg

vA = 2.00 m/s

KB = 7.50 J

a) KA = ?

b) vB = ?

c) W = ?

We can apply the folowing equations

K = 0.5*m*v²

and

W = ΔK = KB- KA

then

a) KA = 0.5*m*vA² = 0.5*(0.600 kg)*(2.00 m/s)²

⇒  KA = 1.2 J

b) KB = 0.5*m*vB²     ⇒     vB = √(2*KB / m)

⇒     vB = √(2*7.50 J / 0.600 kg)

⇒     vB = 5.00 m/s

c) W = ΔK = KB- KA = (7.50 J) - (1.2 J)

⇒     W = 6.30 J

5 0
4 years ago
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