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Mazyrski [523]
3 years ago
9

Give the number of significant figures 6.32 g

Chemistry
2 answers:
labwork [276]3 years ago
6 0
There are 3 significant figures. significant figures are all digits that are not zeros. as well as all zeros that would NOT change the number if removed. i know it seems backwords but they are significant to telling where the measurement ends.
shtirl [24]3 years ago
4 0
There are 3 sig figs
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Chlorine + Calcium --> Ionic Bond
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4 years ago
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How many moles of O2 are required to react with 6.6 moles of H2?
Bingel [31]

<u>Answer: </u>

<u>For 1:</u> 3.3 moles of oxygen gas is required.

<u>For 2:</u> 14 moles of hydrogen gas is required.

<u>For 3:</u> 1.5 moles of oxygen gas is required.

<u>Explanation:</u>

The chemical reaction of oxygen and hydrogen to form water follows:

O_2+2H_2\rightarrow 2H_2O

  • <u>For 1:</u> When 6.6 moles of H_2 is reacted.

By Stoichiometry of the above reaction:

2 moles of hydrogen gas reacts with 1 mole of oxygen gas.

So, 6.6 moles of hydrogen gas will react with = \frac{1}{2}\times 6.6=3.3mol of oxygen gas.

Hence, 3.3 moles of oxygen gas is required.

  • <u>For 2:</u> When 7.0 moles of O_2 is reacted.

By Stoichiometry of the above reaction:

1 mole of oxygen gas reacts with 2 moles of hydrogen gas.

So, 7 moles of oxygen gas will react with = \frac{2}{1}\times 7=14mol of hydrogen gas.

Hence, 14 moles of hydrogen gas is required.

  • <u>For 3:</u> When 3.0 moles of H_2O is formed.

By Stoichiometry of the above reaction:

2 moles of water is formed from 1 mole of oxygen gas.

So, 3.0 moles of water will be formed from = \frac{1}{2}\times 3.0=1.5mol of oxygen gas.

Hence, 1.5 moles of oxygen gas is required.

7 0
3 years ago
Please help me <br> Vote you brainiest but please just help
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Their average speed during the trip is 53 km/ hr approximately

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4 0
3 years ago
0.7 L of H2 enters a reaction at standard temperature and pressure.
ASHA 777 [7]

Answer:

1.88 × 10²³ particles

Explanation:

Given data:

Volume of H₂ = 0.7 L

Number of particles at STP = ?

Solution:

First of all we will calculate the number of moles of H₂.

PV = nRT

n = PV / RT

n = 1 atm . 7 L / 0.0821 L. atm. mol⁻¹. k⁻¹ × 273.15 K

n = 7 atm. L / 22.43 L. atm. mol⁻¹

n = 0.312 mol

it is known that,

2 g H₂ = 1 mol = 6.022 × 10²³ particles

For 0.312 mol

              0.312 × 6.022 × 10²³ particles

                    1.88 × 10²³ particles

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When iron reacts with oxygen to form rust, each iron atom
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Answer is in that reaction each iron atom loses three elections
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