Give the number of significant figures 6.32 g

2 answers:

6 0

There are 3 significant figures. significant figures are all digits that are not zeros. as well as all zeros that would NOT change the number if removed. i know it seems backwords but they are significant to telling where the measurement ends.

shtirl [24]3 years ago

4 0

There are 3 sig figs

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Tuliskan persamaan tetapan kesetimbangan untuk reaksi-reaksi berikut a. Fe3+(aq) + SCN– (aq) ↔ FeSCN3+(aq) b. 3Fe(s) + 4H2O(g) ↔

nevsk [136]

Answer:

a. $K_c = \dfrac{[ FeSCN^{3+}_{(aq)}] }{[Fe^{3+}_{(aq)}] [SCN^-_{(aq)}]}$

b. $K_p = \dfrac{[H_2]^4}{[H_2O]^4}$

Explanation:

Untuk semua jenis reaksi umum:

$aA + bB\iff cC + dD$

Konstanta kesetimbangan $K_c = \dfrac{[C]^c [D]^d}{[A]^a[B]^b}$

Dari pertanyaan yang diberikan:

a. $Fe3^+_{(aq)} + SCN^-_{ (aq)} \iff FeSCN^{3+}_{(aq) }$

Konstanta kesetimbangan:

$K_c = \dfrac{[ FeSCN^{3+}_{(aq)}] }{[Fe^{3+}_{(aq)}] [SCN^-_{(aq)}]}$

b. $3Fe_{(s)} + 4H_2O_{(g)} \iff Fe_3O_4_{(s)} + 4H_{2(g)}$

Konstanta kesetimbangan untuk tekanan parsial $K_p$

$K_p = \dfrac{[H_2]^4}{[H_2O]^4}$

Karena Fe3O4 (s) hadir sebagai padatan.

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2 years ago

What is the threshold frequency ν0 of cesium?

Montano1993 [528]

I think this is what you're after:

Cs(g) → Cs^+ + e⁻ ΔHIP = 375.7 kJ mol^-1 [1]

Convert to J and divide by the Avogadro Const to give E in J per photon

E = 375700/6.022×10^23 = 6.239×10^-19 J

Plank relationship E = h×ν E in J ν = frequency (Hz s-1)

Planck constant h = 6.626×10^-34 J s

6.239×10^-19 = (6.626×10^-34)ν

ν = 9.42×10^14 s^-1 (Hz)

IP are usually given in ev Cs 3.894 eV

<span>E = 3.894×1.60×10^-19 = 6.230×10^-19 J per photon </span>

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