Neither energy nor matter can enter and exit an isolated system.
Explanation:
There are three types of systems which refers to universe. They are
1. Open System : In an open system, both energy and matter have external interactions. Example:- boiling water in an open pan.
2. Closed system : In a closed system, only energy has interaction with surroundings. Example:- boiling water with a lid on the pan.
3. Isolated system : In an isolated system, neither energy-nor matter has external interactions with surroundings. Example : a thermos flask does not exchange energy and matter.
Hence, the correct option is (a) " neither energy nor matter ".
1. Friction (Example: when you rub your hands together and you start to feel heat.)
2. Attract each other. (Example: Every object has a gravitational pull of some sort. The larger the object, the stronger the gravitational pull. This is why the sun is able to keep all eight planets in orbit around it.)
3. Hope this helped :)
Answer:
B) The car at point C has less kinetic energy than the car at point B.
Explanation:
We have two types of energy involved in this situation:
- Gravitational potential energy: this is the energy related to the heigth of the car, and it is given by
, where m is the mass of the car, g is the gravitational acceleration, and h is the heigth of the car. The potential energy is higher when the car is located higher above the ground.
- Kinetic energy: this is the energy due to the motion of the car, and it is given by
, where m is the mass of the car and v is its speed. The kinetic energy is higher when the speed of the car is higher.
- The law of conservation of energy states that the total mechanical energy of the car (sum of potential energy and kinetic energy:
) is constant). This implies that when the car is at a higher point, the kinetic energy is less (because U is larger, so K must be smaller), while when the car is at a lower point, the kinetic energy is larger.
- Based on what we have written so far, we can conclude that the correct statement is:
B) The car at point C has less kinetic energy than the car at point B.
Because the car at point C is located at a higher point than point B, so the car at point C has larger potential energy than at point B, which implies that car at point C has less kinetic energy than the car at point B.
Answer:
C. 1400
Explanation:
The force exerted = f1 = 250
Diameter d1 = 0.02
r1 = d1/2 = 0.01
Diameter d2 = 0.15
r2 = d2/2 = 0.075
The mass of jack to lift
F1/A1 = f2/A2
250/r1² = f2/r2²
250/0.01² = f2/0.075²
When we cross multiply, we will have:
250x0.005625 = 0.0001f2
1.40625 = 0.0001f2
F2 = 1.40625/0.0001
F2 = 14062.5N
Force f = mg
g = 9.81
m = 14062.5/9.81
Mass = 1433Kg
Therefore option c is correct. A mass of 1400kg can be lifted by the jack
A) The friction force while the box is stationary is (the coefficient of static friction)*(the normal force). In this case, the normal force is equal to the gravitational force, or the weight. To move the box, we need a minimum horizontal force that is equal to the friction force. The weight is (500 kg)*(9.81 m/s^2)= 4905 N. So, (0.45)*(4905 N) = 2207.25 N.
b) The acceleration will be the horizontal force - the kinetic friction force (since they act in opposite directions) divided by the mass. Kinetic friction force = (coefficient of kinetic friction)*(normal force or weight).
F(net) = (2207.25 N)-(0.30)(4905 N) = 735.75 N
a = (735.75 N)/(500kg)= 1.4715 m/s^2