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3 years ago

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(7%) Problem 5: A thermos contains m1 = 0.73 kg of tea at T1 = 31° C. Ice (m2 = 0.095 kg, T2 = 0° C) is added to it. The heat ca

pacity of both water and tea is c = 4186 J/(kg⋅K), and the latent heat of fusion for water is Lf = 33.5 × 104 J/kg. [email protected]

1 answer:

klio [65]3 years ago

8 0

Could you explain a little more?

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Is it possible for a nazi style government to exist in the modern world? Explain why or why not.

nevsk [136]

I think only if they were too overpowered maybe, but the modern world doesn't except this kind of dictatorship. Most armies are much more powerful than in the past.

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4 years ago

You find an unmarked blue laser on your way to physics class. When you get to class you realize you can determine the wavelength

Afina-wow [57]

Answer:

λ = 451.7 nm

Explanation:

The expression for the constructive interference of the double diffraction experiment is

d sin θ = m λ

let's use trigonometry

tan θ = y / L

how the experiment occurs at very small angles

tan θ = sin θ / cos θ = sin θ

sin θ = y / L

we substitute

d y / L = m λ

λ = $\frac{d \ y}{m \ L}$

let's calculate

λ = $\frac{0.342 \ 10^{-3} \ 2.80 \ 10^{-3} }{1 \ 2.12 }$

λ = 4.51699 10⁻⁷ m

λ = 4.517 10⁻⁷ m (109 nm / 1m)

λ = 451.7 nm

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3 years ago

Dos cargas Q1=2pc y Q2=4pc estan separadas por una distancia de 6cm ¿con que fuerza se atraen?

noname [10]

Here we can use coulomb's law to find the force between two charges

As per coulombs law

]tex]F = \frac{kq_1q_2}{r^2}[/tex]

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$k = 9 * 10^9$

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$F = \frac{9*10^9 * 2*10^{-12} * 4*10^{-12}}{0.06^2}$

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3 0

3 years ago

When compared to

ElenaW [278]

I think it is B, because the sun’s size is pretty average

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3 years ago

A 55.0-g sample of hot metal initially at 99.5oC was added to 40.0 g of water in a Styrofoam coffee cup calorimeter. The water a

Kaylis [27]

Answer:

Cp= 0.44 J/g.C

This is heat capacity of metal.

Explanation:

From energy conservation

Heat lost by metal = Heat gain by water +Heat gain by calorimeter

Because here temperature of metal is high that is why it loose the heat.The temperature of water and calorimeter is low that is why they gain the heat.

final temperature is T= 30.5 C

We know that sensible heat transfer given as

Q= m Cp ΔT

m=Mass

Cp=Specific heat capacity

ΔT=Temperature difference

By putting the values

55 x Cp ( 99.5 - 30.5) = 40 x 4.184 ( 30.5- 21 ) + 10 x ( 30.5 - 21)

Cp ( 99 .5- 30.5) = 30.65

Cp= 0.44 J/g.C

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4 0

4 years ago