Answer:
<h2>
=9-12+12</h2>
Step-by-step explanation:
<h2>=n²- 4n + 12</h2><h2>=(3)²- 4(3) + 12</h2><h2>=9-12+12</h2>
I don't know if it's correct
Answer:
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Step-by-step explanation:NWEKFK.EWBFEWHBV.KWEUF67OFVD.KFERLUGVK34UGILBEFLIUBYETRNTYM6
The domain of a function is the set of values of x for which a value of y exists. In this case, the only way that a value of y would not exist is for a denominator to equal to zero. If this function is f(x) = 1/(x+1) + 5, then we must find the values of x for which the denominator (x+1) = 0, which is at x = -1.
Therefore the domain is all real numbers except x = -1. In interval notation this can be written as (-infinity, -1), (-1, infinity).
P can be a range of numbers from 3 to 5.
The answer to this question is true