Answer:
<h2>Magnitude of the second charge is
</h2>
Explanation:
According to columbs law;
F = 
F is the attractive or repulsive force between the charges = 12N
q1 and q2 are the charges
let q1 = - 8.0 x 10^-6 C
q2=?
r is the distance between the charges = 0.050m
k is the coulumbs constant =9*10⁹ kg⋅m³⋅s⁻⁴⋅A⁻²
On substituting the given values
12 = 9*10⁹*( - 8.0 x 10^-6)q2/0.050²
Cross multiplying
Answer:
Bok.............................
Answer:
gravitational potential energy of 10 kg mass is 122.625 J
Explanation:
Gravitational Potential energy gain is given as
here we know that
m = 10 kg
h = 1.25 m
now from above formula we have
So gravitational potential energy of 10 kg mass is 122.625 J
The magnetic force on a charged particle is given as: F = qvBsinФ
B is the magnetic field.
q is the charge on the particle.
v is the velocity of the charged particle.
Ф is the angle between magnetic field (B) & the velocity of charge (v).
⇒ F = qvb sin Ф
Here, Ф = 90 degree.
and sin 90 = 1
Putting the values in the equation, we get,
F = 1.6 x 10^-19 C × 4.5 × 10^7 m/s × 1.6 T
= 11.52 × 10^-12N
= 1.2 x 10^-11 N up
The restoring force on the spring is found to have exactly the same magnitude as the stretching force. Option D
<h3>What is the restoring force?</h3>
The restoring force is the force that seeks to restore the spring to its equilibrium position. It has the same magnitude as the stretching force but acts in opposite direction.
Thus, the restoring force on the spring is found to have exactly the same magnitude as the stretching force.
Learn more about restoring force:brainly.com/question/12162527
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