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NNADVOKAT [17]
3 years ago
10

Layers of Earth's Atmosphere

Physics
1 answer:
Tamiku [17]3 years ago
3 0

Answer:

going to work my way down

Troposphere

contains weather

contains life forms

stratosphere

contains ozone layer

mesosphere

where asteroids burn up

very low temps

thermosphere

widely varying temps

exosphere

almost no molecules

Explanation:

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If an impulse of 400 Ns acts on an object for 15s, what is the force of the object?
Ksju [112]

Answer:

J for impulse

t for time

F for force

formula is J=F×t

Explanation:

putting values in eqs after rearranging

we need to find force so

F=J ÷t

F=400÷15

=26.67

=27(rounded off)

27N is the Force applied.

7 0
3 years ago
_____________ forces are always attractive and the mass of an object determines how strong the ____________ pull is.
dolphi86 [110]
Gravitational, gravitational ! both the option are same
6 0
3 years ago
In 2005 astronomers announced the discovery of a large black hole in the galaxy Markarian 766 having clumps of matter orbiting a
IRISSAK [1]

A. 4.64\cdot 10^{11}m

The orbital speed of the clumps of matter around the black hole is equal to the ratio between the circumference of the orbit and the period of revolution:

v=\frac{2\pi r}{T}

where we have:

v=30,000 km/s = 3\cdot 10^7 m/s is the orbital speed

r is the orbital radius

T=27 h \cdot 3600 =97,200 s is the orbital period

Solving for r, we find the distance of the clumps of matter from the centre of the black hole:

r=\frac{vT}{2\pi}=\frac{(3\cdot 10^7 m/s)(97200 s)}{2\pi}=4.64\cdot 10^{11}m

B. 6.26\cdot 10^{36}kg, 3.13\cdot 10^6 M_s

The gravitational force between the black hole and the clumps of matter provides the centripetal force that keeps the matter in circular motion:

m\frac{v^2}{r}=\frac{GMm}{r^2}

where

m is the mass of the clumps of matter

G is the gravitational constant

M is the mass of the black hole

Solving the formula for M, we find the mass of the black hole:

M=\frac{v^2 r}{G}=\frac{(3\cdot 10^7 m/s)^2(4.64\cdot 10^{11} m)}{6.67\cdot 10^{-11}}=6.26\cdot 10^{36}kg

and considering the value of the solar mass

M_s = 2\cdot 10^{30}kg

the mass of the black hole as a multiple of our sun's mass is

M=\frac{6.26\cdot 10^{36} kg}{2\cdot 10^{30} kg}=3.13\cdot 10^6 M_s

C. 9.28\cdot 10^9 m

The radius of the event horizon is equal to the Schwarzschild radius of the black hole, which is given by

R=\frac{2MG}{c^2}

where M is the mass of the black hole and c is the speed of light.

Substituting numbers into the formula, we find

R=\frac{6.26\cdot 10^{36} kg)(6.67\cdot 10^{-11})}{(3\cdot 10^8 m/s)^2}=9.28\cdot 10^9 m

8 0
2 years ago
A car starts from rest with an acceleration of 2.84 m/s2 at the instant when a second car moving with a velocity of 25.7 m/s pas
vredina [299]

Answer:

464.69 m

Explanation:

First car

s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times t+\frac{1}{2}2.84t^2\\\Rightarrow s=1.42t^2

Second car

Distance = Speed × Time

\text{Distance}=25.7t

Here, the time taken and the distance traveled will be the same

Equating the two equations

1.42t^2=25.7t\\\Rightarrow t=\frac{25.7}{1.42}\\\Rightarrow t=18.09\ s

So, the first would have to move 1.42t^2=1.42\times 18.09^2=464.69\ m in order to overtake the second car.

7 0
3 years ago
As a transverse wave travels through a rope from left to right, the parts of the rope _______.
kupik [55]
<h3><u>Answer;</u></h3>

Are moving up and down.

As a transverse wave travels through a rope from left to right, the parts of the rope <u>are moving up and down</u>.

<h3><u>Explanation;</u></h3>
  • Transverse waves occur when a disturbance causes oscillations perpendicular to the propagation, that is the direction of energy transfer.
  • <em><u>Particles of the medium move perpendicular to the direction the transverse wave itself is moving.  For example, if the wave is moving to the right, the particles of the medium are moving up and down.</u></em>
  • <em><u>Therefore, as a transverse wave travels through a rope from left to right, the parts of the rope are moving up and down.</u></em>
8 0
3 years ago
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