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svet-max [94.6K]
2 years ago
6

What is the work required to lift a 10 kg box off the ground to a height of 5.0 m?

Physics
1 answer:
FinnZ [79.3K]2 years ago
7 0

Answer:

490J

Explanation:

Given parameters:

Mass of box  = 10kg

Height  = 5m

Unknown:

Work done  = ?

Solution:

Work done can be derived from the product of force and distance;

   Work done = force x distance

 Force here is applied by gravity and it is the weight

 The distance is the height

  Work done  = weight x height

 Work done  = mass x acceleration due to gravity x height

 Work done  = 10 x 9.8 x 5  = 490J

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Could someone answer this?
Nadusha1986 [10]

Answer:

Here the circuit in which a 4Ω resistor resistor is connected in series and two 8Ω resistor resistors are connected in parallel. Also, ammeter and voltmeter connected in series and parallel circuit respectively.

Now,

The maximum power of each resistance is 16 W

The 4Ω resistor is linked in series with the circuit.

so, P o w e r = I

two

R, here i is the current through the resistor resistor R

1 6 = I

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∗ 4 Ω

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Now 2A passes through parallel resistors of 8Ω resistance.

we know that, in parallel, the potential difference must be constant,

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I hope this answer has helped you

6 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST!!!
Elan Coil [88]

The spring constant is 181.0 N/m

Explanation:

We can solve the problem by applying the law of conservation of energy. In fact, the elastic potential energy initially stored in the compressed spring is completely converted into gravitational potential energy of the dart when the dart is at its maximum height. Therefore, we can write:

\frac{1}{2}kx^2 = mgh

where the term on the left represents the elastic potential energy of the spring while the term on the right is the gravitational potential energy of the dart at maximum height, and where

k is the spring constant of the spring

x = 2.08 cm = 0.0208 m is the compression of the spring

m = 12.3 g = 0.00123 kg is the mass of the dart

g=9.8 m/s^2 is the acceleration due to gravity

h = 3.25 m is the maximum height of the dart

Solving for k, we find:

k=\frac{2mgh}{x^2}=\frac{2(0.00123)(9.8)(3.25)}{(0.0208)^2}=181.0 N/m

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

6 0
3 years ago
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