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natita [175]
3 years ago
9

Let mAngleA = 40°. If AngleB is a complement of AngleA, and AngleC is a supplement of AngleB, find these measures.

Physics
2 answers:
VMariaS [17]3 years ago
8 0

Answer:

Angle B =50

Angle C =130

Explanation:

Nikitich [7]3 years ago
7 0

Answer:

mAngleB= 50

mAngleC= 130

Explanation:

Complementary angles = 90

So If angle A is 40 subtract that to 90 to find angle B which is 50

and 50+40= 90 = Complementary

Supplementary angles = 180

So if angle C is supplementary to angle B you would need to subtract 50 from 180 to find angle C which is 130

130+20= 180 = supplementary  

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A conical container of radius 6 ft and height 24 ft is filled to a height of 19 ft of a liquid weighing 64.4 lb divided by ft cu
kobusy [5.1K]

Answer:

Part (i) work required to pump the contents to the​ rim is 281,913.733 lb.ft

Part (ii) work required to pump the liquid to a level of 5ft above the​ cone's rim is 426,484.878 lb.ft

Explanation:

The center of mass of a uniform solid right circular cone of height h lies on the axis of symmetry at a distance of h/4 from the base and 3h/4 from the top.

Center mass of the liquid Z = (24-19)ft + 19/4 = 5ft + 4.75ft = 9.75 ft

Mass of liquid in the cone = volume × density (ρ) =  ¹/₃.π.r².h.ρ

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h is the height of the liquid = 19 ft

Mass of liquid in the cone = ¹/₃ × π × (4.75)² × 19 × 64.4 = 28,914.229 lbs

Part (i)  work required to pump the contents to the​ rim

Work required = 28,914.229 lbs × 9.75 ft = 281,913.733 lb.ft

Part (ii) work required to pump the liquid to a level of 5 ft above the​ cone's rim

Extra work required = 28,914.229 lb ×  5ft = 144571.145 lb.ft

Total work required = (281,913.733 +  144571.145) lb.ft

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3 years ago
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