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3 years ago

Someone please help me answer this !!!

Physics

1 answer:

Elan Coil [88]3 years ago

7 0

Answer:

I think its C sorry if it's wrong

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A camcorder has a power rating of 15 watts. If the output voltage from its battery is 5 volts, what current does it use?

MrMuchimi

Formula

W = E * I

Givens

E = 5 volts

W = 15 watts

I = ?

Solution

W = E * I

15 = 5 * I

15/5 = I

I = 3 amps. Answer

5 0

2 years ago

A train 471 m long is moving on a straight track with a speed of 75.1 km/h. The engineer applies the brakes at a crossing, and l

hram777 [196]

Answer:

$t = 37.6 s$

Explanation:

As we know that train is initially moving with the speed

$v_i = 75.1 km/h$

now we know that

$v_i = 20.86 m/s$

now the final speed of the train when it crossed the crossing

$v_f = 15 km/h$

$v_f = 4.17 m/s$

now we can use kinematics here

$v_f^2 - v_i^2 = 2 a d$

$4.17^2 - 20.86^2 = 2 a(471)$

$a = -0.44 m/s^2$

Now the time to cross that junction is given as

$v_f - v_i = at$

$4.17 - 20.86 = a(-0.44)$

$t = 37.6 s$

4 0

2 years ago

A little help please?

Tpy6a [65]

A. Made of the marble.

the mass remains constant when you drop the marble but the rest of the variables change as the marble is dropped, therefore, the only constant variable is its mass.

7 0

3 years ago

An unstretched spring has a length of 0.30 m. When the spring is stretched to a total length of 0.60 m, it supports traveling wa

IceJOKER [234]

Explanation:

Below is an attachment containing the solution

7 0

2 years ago

A diode vacuum tube consists of a cathode and an anode spaced 5-mm apart. If 300 V are applied across the plates. What is the ve

MAXImum [283]

Answer:

Explanation:

There is electric field between the plates whose value is given by the following expression

electric field E = V /d where V is potential between the plates and d is distance between them

E = 300 / 5 x 10⁻³

= 60 x 10³ N/c

Force on electron = q E where q is charge on the electron

F = 1.6 X 10⁻¹⁹ X 60 X 10³ = 96 X 10⁻¹⁶ N.

Acceleration a = force / mass

a = 96 x 10⁻¹⁶/ mass = 96 x 10⁻¹⁶ / 9.1 x 10⁻³¹

= 10.55 x 10¹⁵ m / s²

For midway , distance travelled

s = 2.5 x 10⁻³ m

s = 1\2 a t²

t = $\sqrt{\frac{2s}{a\\ } }$

= $\sqrt{\frac{2\times2.5\times10^{-3}}{ 10.55\times10^{15}}$

t = .474 x 10⁻¹⁸ s

For striking the plate time is calculated as follows

t = $[tex]\sqrt{\frac{2\times5\times10^{-3}}{ 10.55\times10^{15}}$ [/tex]

t = 0.67 x 10⁻¹⁸ s

3 0

3 years ago