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3 years ago

For two variables that are inversely related, what is the result of doubling one variable?

2 answers:

5 0

Roses are red, violets are blue. the answer were all looking for, is 42.
grass is green, yogis are lean, me---well i'm just mean.
now just one more, before i go. OMG look out your window!!!!!

did i get ya? no? ok then.

iVinArrow [24]3 years ago

3 0

the other variable is halved.

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The land between two normal faults moves upward to form a

Leya [2.2K]

<span>The land between two normal faults moves upward to form a

Answer:D</span><span>
fault-block mountain.</span>

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3 years ago

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How long does it take an object to travel 375 m at a rate of 25 m/s?

Leni [432]

Answer:

15s

Explanation:

Given parameters:

Distance traveled = 375m

Speed = 25m/s

Unknown:

Time taken = ?

Solution:

To solve this problem, we make time the subject of the speed equation.

Speed = $\frac{distance}{time}$

Time = $\frac{distance}{speed}$

Now insert the parameters and solve;

Time = $\frac{375}{25}$ = 15s

3 0

3 years ago

Most people would consider a comfortable room temperature to be

Alla [95]

A is extremly hot

and c is -330.07 degrees farenheit

4 0

3 years ago

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A SMALL cup of tea has water inside that is very hot, about 80 degrees Celsius. A LARGE bathtub has water inside it that is warm

Artist 52 [7]

Answer:

the water in the tea cup

Explanation:

Kinetic energy is the energy an object or particles possesses as a result of motion.

Liquid in higher temperature possesses more kinetic energy than liquid with lower temperature

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3 years ago

A 5.0-kilogram sphere, starting from rest, falls freely 22 meters in 3.0 seconds near the surface of a planet. Compared to the a

Whitepunk [10]

Answer:

C) one-half as great

Explanation:

We can calculate the acceleration of gravity in that planet, using the following kinematic equation:

$\Delta x=v_0t+\frac{gt^2}{2}$

In this case, the sphere starts from rest, so $v_0=0$ . Replacing the given values and solving for g':

$g'=\frac{2\Delta x}{t^2}\\g'=\frac{2(22m)}{(3s)^2}\\g'=4.89\frac{m}{s^2}$

The acceleration due to gravity near Earth's surface is $g=9.8\frac{m}{s^2}$ . So, the acceleration due to gravity near the surface of the planet is approximately one-half of the acceleration due to gravity near Earth's surface.

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3 years ago