Answer:
Step-by-step explanation:
for qn 14 use the SOH CAH TOA method
use cos for this so. cos 47 degree= x/13
solve for x.
Do recall that squaring and the *radical sign* cancel each other out... like so:(

)

= a
When you put it that way, it isn't enough :P
(

)

= a
(

)

=?
so you start with
(

)

=

8x+1=25 <-- subtract 1 to both sides
8x=24 <- divide 8 to both sides
x= 3
To find out if it's an extraneous solution ask yourself: It mustn't result in a radical that I like to call... 'illegal'. Plug it into the radicand 8x+1 and make sure you get something that is not a negative number.... so, DO you get a negative number when you plug in x = 3 into the radicand?
(extraneous solution is a invalid solution)
x=3 not extraneous
The answer to this question is 9
I took five years before and it was hard for me to remember the postualates. I found it helpful to practice proving problems that involved the postualate. Some postualates like SAS are just abbreviations. SAS- Side-Angle-Side