Solution :
Let
kg
m/s
Let
and
are the speeds of the disk
and
after the collision.
So applying conservation of momentum in the y-direction,





Therefore, the disk 2 have greater velocity and hence more kinetic energy after the collision.
Now applying conservation of momentum in the x-direction,




m/s
So, 
= 4.33 m/s
Therefore, speed of the disk 2 after collision is 4.33 m/s
Answer:
emf = 11.667 V
Explanation:
Given: charge q = 0.060 C, electric potential energy E =0.70 J,
Solution :
by definition 1 volt = 1 joule per coulomb
so Voltage = emf = E/C
emf = 0.70 J / 0.060 C
emf = 11.667 V
The distance that light moves in a year is called a light year.
2) Light-year.
The correct answer is
<span>A. Liquid water could exist there.
In fact, liquid water is fundamental for life. So, one of the conditions to define the habitable zone around a star is that the temperature allows the presence of liquid water.</span>