All categories

3 years ago

calculate the mass of potassium chlorate (kcio3) required to obtain 10g of oxygen in the following reaction:kclO3-kcl+O2

Physics

1 answer:

igor_vitrenko [27]3 years ago

7 0

First, balance the reaction:

_ KClO₃ ==> _ KCl + _ O₂

As is, there are 3 O's on the left and 2 O's on the right, so there needs to be a 2:3 ratio of KClO₃ to O₂. Then there are 2 K's and 2 Cl's among the reactants, so we have a 1:1 ratio of KClO₃ to KCl :

2 KClO₃ ==> 2 KCl + 3 O₂

Since we start with a known quantity of O₂, let's divide each coefficient by 3.

2/3 KClO₃ ==> 2/3 KCl + O₂

Next, look up the molar masses of each element involved:

• K: 39.0983 g/mol

• Cl: 35.453 g/mol

• O: 15.999 g/mol

Convert 10 g of O₂ to moles:

(10 g) / (31.998 g/mol) ≈ 0.31252 mol

The balanced reaction shows that we need 2/3 mol KClO₃ for every mole of O₂. So to produce 10 g of O₂, we need

(2/3 (mol KClO₃)/(mol O₂)) × (0.31252 mol O₂) ≈ 0.20835 mol KClO₃

KClO₃ has a total molar mass of about 122.549 g/mol. Then the reaction requires a mass of

(0.20835 mol) × (122.549 g/mol) ≈ 25.532 g

of KClO₃.

You might be interested in

Your car and the trailer it is towing are initially at rest. you apply an acceleration of 1.75 m/s2 to get the vehicles moving.

kirza4 [7]

The net force is defined as the vector sum of all the forces that are present in an object. The formula for net force is F=ma. Everything else cancels out like the force of gravity on the car, and the reactive force of the road surface, etc. It can be concluded that the force exerted by the trailer on the car is the same as that exerted by the car on the trailer. Given that the acceleration is 1.75 m/s^2, the car is 1200 kilograms, and the trailer is 540 kilograms. Thus, the net force acting on the car is equal to 21qkm/hr^2

4 0

4 years ago

In Bolt’s fastest 100 meter, he accelerated from the starting block to a speed of 27.8 mi/hr in 9.58 s. What was his acceleratio

Gemiola [76]

Answer: 2.90mi/hr/s

Explanation:

Acceleration = Final Velocity - Initial over time

Acceleration = 27.8mi/hr over 9.58s.

Answer is 2.90mi/hr/s

Hope I Helped!

8 0

2 years ago

The volume flow rate of blood leaving the heart to circulate throughout the body is about 5 L/min for a person at rest. All this

skelet666 [1.2K]

Answer:

$n=2.9\times 10^9$

$A=1.88\times 10^{-8}\ m^2$

Explanation:

Given that

Q= 5 L/min

1 L = 10⁻³ m³/s

1 min = 60 s

Q=0.083 x 10⁻³ m³/s

d= 6 μm

v= 1 mm/s

So the discharge flow through one tube

q = A v

$A=\dfrac{\pi}{4}d^2$

$A=\dfrac{\pi}{4}\times (6\times 10^{-6})^2\ m^2$

A=2.8 x 10⁻¹¹ m²

v= 1 x 10⁻³ m/s

q= 2.8 x 10⁻¹⁴ m³/s

Lets take total number of tube is n

Q= n q

n=Q/q

$n=\dfrac{0.083\times 10^{-3} }{ 2.8\times 10^{-14}}$

$n=2.9\times 10^9$

Surface area A

A= π d L

$A=\pi \times 6\times 10^{-6}\times 10^{-3}\ m^2$

$A=1.88\times 10^{-8}\ m^2$

7 0

3 years ago

Sabiendo que el indice de refracción dela gua es 1,33 calcula el ángulo de refracción resultante para un rayo de luz que incide

Kaylis [27]

Answer:

35.16 degrees

Explanation:

Knowing that the index of refraction of the guide is 1.33, calculate the resulting angle of refraction for a ray of light that falls on a pool with an angle of incidence of 50º

Refractive index, n = 1.33

The angle of incidence, i = 50°

We need to find the angle of refraction. let it is r. It can be calculated using Snells law as follows:

$n=\dfrac{\sin i}{\sin r}\\\\\sin r=\dfrac{\sin i}{n}\\\\r=\sin^{-1}(\dfrac{\sin i}{n})\\\\r=\sin^{-1}(\dfrac{\sin 50}{1.33})\\\\r=35.16^{\circ}$

So, the angle of refraction is 35.16 degrees.

3 0

3 years ago

What erases the impact craters on earth and is responsible for most of the landforms that we see?

frez [133]

The big bang theory I think

6 0

3 years ago

calculate the mass of potassium chlorate (kcio3) required to obtain 10g of oxygen in the following reaction:kclO3-kcl+O2​

calculate the mass of potassium chlorate (kcio3) required to obtain 10g of oxygen in the following reaction:kclO3-kcl+O2