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2 years ago

Now review the difference between the temperatures on Earth and Mars. Also look at their distances from the sun.

Physics

2 answers:

aksik [14]2 years ago

7 0

Answer: Use Question cove you can get it faster you can get the answer faster! ;) hope this helps ;) but yeah use that and answer is done right away

Explanation: HOPE THIS HELPSS!! ;))

DaniilM [7]2 years ago

5 0

Answer:

They are related because the more distance away from the sun is colder while getting closer to the sun will start making it hot

I already wrote it in the other question

<u><em>PLS MARK BRAINLIEST</em></u>

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In the form of radioactive decay known as alpha decay, an unstable nucleus emits a helium-atom nucleus, which is called an alpha

Assoli18 [71]

Answer:

$\mathbf{v_a = 4.06 \times 10^7 \ m/s}$

Explanation:

$\text{The missing part of the question is attached below.} \\ \\ \text{ mass m = 4u and charge q = 2e. Suppose a uranium nucleus with 92 protons decays into }$ $\text{into thorium, with 90 protons, and an alpha particle. The alpha particle is initally at rest at }$ $\text{ the surface of the thorium nucleus, which is 15 fm in diameter. What is the speed of the alpha}$ $\text{particle when it is detected in the laboratory? Assume the thorium nucleus remains at rest. }$

$\text{So, from the above infromation;}$

$radius (r) = \dfrac{15 \ fm }{2}$

$radius (r) = 7.5 \times 10^{-15} \ m$

$\text{Using the formula for potential energy}$

$U = \dfrac{(9\times 10^9 \ Nm^2/C^2)(2(1.6\times10^{-19} \ C ))(90)(1.6\times 10^{-19} C)}{7.5 \times 10^{-13} \ m}$

$U = 5.529 \times 10^{-12} \ J$

$\text{Now, the speed of the alpha particle can be estimated from the conservation of energy principle}$ $\dfrac{1}{2}mv_a^2= 5.529 \times 10^{-12} J$

$v_a = \sqrt{\dfrac{2(5.529 \times 10^{-12} \ J)}{4(1.67 \times 106{-37} \ kg)}}$

$\mathbf{v_a = 4.06 \times 10^7 \ m/s}$

4 0

2 years ago

Estimate the number of Ping-Pong balls that can be packed into an average size room (without crushing them). Given that Ping-Pon

scoray [572]

Answer: 3,893,845.918 Ping-Pong balls

Explanation:

The volume of an average room is:

$V_{room}=(length)(width)(height)$ (1)

$V_{room}=(12 ft)(18 ft)(9 ft)=1944 ft^{3}$ (2)

Now let’s transform this $V_{room}$ to units of $cm^{3}$ , knowing $1 ft=30.48 cm$ :

$V_{room}=1944 ft^{3}\frac{{(30.48 cm)}^{3}}{1ft^{3}}=55,047,949.78 cm^{3}$ (3)

On the other hand, we have Ping-Pong balls with a radius $r=1.5 cm$ , and their volume is given by:

$V_{balls}=\frac{4}{3} \pi r^{3}$ (4)

$V_{balls}=\frac{4}{3} \pi (1.5 cm)^{3}$ (5)

$V_{balls}=14.137 cm^{3}$ (6)

Now, the number $n$ of Ping-Pong balls that can be packed into the room is:

$n=\frac{V_{room}}{V_{balls}}$ (7)

$n=\frac{55,047,949.78 cm^{3}}{14.137 cm^{3}}$ (8)

$n=3,893,845.918$ This is the number of Ping-Pong balls that can be packed into an average size room

7 0

3 years ago

If you have an isotope of the element carbon (C) that has the mass number of 14, what other information would help you determine

nirvana33 [79]

Answer:

B) atomic number

Explanation:

- The atomic number (Z) of an element corresponds to the number of protons (p) in its nucleus

- The mass number (A) of an element corresponds to the number of protons (p) + neutrons (n) in the nucleus

We can summarize these two definitions as follows:

Z = p

A = p + n

For the isotope of carbon, we know that the mass number is 14:

A = p + n = 14

Therefore, in order to determine the number of neutrons, we also have to know the atomic number Z, so the number of protons.

In reality, the atomic number of carbon is 6, so Z=6 and we can calculate the number of neutrons in this isotope:

n = A - p = 14 - 6 = 8

7 0

2 years ago

What is the electric field in N/C) at a point where the force on a -2.1 x 10-5 C charge is (4.31 -6.89) x 10-6 N?

krek1111 [17]

Answer: 0.123 N/C

Explanation: In order to solve this question we have to use the electric Force on a particle produced by an electric field which is given by:

F=q*E

so E=F/q= -2,58* 10^-6/-2.1*10^-5= 0.123 N/C

8 0

3 years ago

Let's first consider the dynamics behind the motion in this video. After the student releases the wheel by cutting the cord, wha

nydimaria [60]

Answer:

Hello. You did not provide the video to which the question refers, however, given the context of your question, we can consider that the forces acting on the wheel are the weight of the wheel, the tension that this weight promotes on the rope and the normal force of the axle.

Explanation:

According to the context of the question, we can see that the wheel is being pulled by a rope. The weight of the wheel is the first force that acts on it, promoting resistance to the impulse that the rope promotes on the wheel. When this wheel is pulled by the rope, the weight of the wheel creates tension in the rope, which stretches and becomes tensioned in response to this force. However, this tension is also a force acting on the wheel, as is the normal force on the axis between these two elements.

6 0

2 years ago