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gayaneshka [121]
3 years ago
8

What is the kinetic energy of a hammer that starts from rest and decreases its potential energy by 10 kJ?

Physics
1 answer:
erma4kov [3.2K]3 years ago
3 0

Answer:

final kinetic energy of the hammer is 10 kJ

Explanation:

As we know that there is no non conservative force on the system

So here we can use the theory of mechanical energy conservation

So we will have

\Delta K + \Delta U = 0

here we know that

\Delta U = - 10 kJ

from above expression now

K_f - K_i - 10 kJ = 0

K_f - 0 = 10 kJ

so final kinetic energy of the hammer is 10 kJ

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You move a 25 N object 5 meters. How much work did you do ?
olga55 [171]
The answer is 125 Joules

The first thing to take note of is the work equation: W=F×D

Since we already have our force and our distance that will help make this problem easier.

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Hope this helped!! :)


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3 years ago
The phases of the moon are the changing appearances of the moon, as seen from Earth. Which phase happens immediately after a thi
Drupady [299]

The phases of the moon are the changing appearances of the moon, as seen from Earth. Which phase happens immediately after a third quarter moon are the following

Explanation:

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waning gibbous phase

  • The waning gibbous phase occurs between the full moon and third quarter phases. The last quarter moon (or a half moon) is when half of the lit portion of the Moon is visible after the waning gibbous phase.

Time takes by the moon to go through all the phases

about 29.5 days

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6 0
3 years ago
Read 2 more answers
A satellite with a mass of 2,000 ㎏ is inserted into an orbit that is twice the Earth' s radius. W hat is the force of gravity on
dolphi86 [110]

Answer:

option (b) 4900 N

Explanation:

m = 2000 kg, R = 6380 km = 6380 x 10^3 m, Me = 5.98 x 10^24 kg, h = R

F = G Me x m / (R + h)^2

F = G Me x m / 2R^2

F = 6.67 x 10^-11 x 5.98 x 10^24 x 2000 / (2 x 6380 x 10^3)^2

F = 4900 N

4 0
3 years ago
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