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Sunny_sXe [5.5K]
3 years ago
12

I need percentage, fraction, decimal That are equivalent asapppp

Mathematics
2 answers:
Anarel [89]3 years ago
6 0

Answer:

3/5 = 0.6

1/8 = 0.125

3/50 = 0.06

7/8 = 87.5%

1/3 = 33 1/3%

hope this helped.. brainliest??

12345 [234]3 years ago
4 0

Answer:3/5 = 0.6

1/8 = 0.125

3/50 = 0.06

7/8 = 87.5%

1/3 = 33 1/3%

Step-by-step explanation:

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How many 3/8s are in 6
dlinn [17]

Answer:

16

Step-by-step explanation:

6 divided by 3/8=6*8/3=48/3=16

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There is 6/8 of a cake leftover after a birthday party. How many 1/4 pieces can be made out of the leftover cake?
ikadub [295]

3/4 because if you make it smaller you would get that

4 0
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Ad is tangent to circle o at d. find ab. round to the nearest tenth if necessary
Naddik [55]
Check the picture below.

\bf 0=AB^2+6AB-121\implies \stackrel{\textit{using the quadratic formula}}{AB=\cfrac{-6 \pm \sqrt{6^2-4(1)(-121)}}{2(1)}}
\\\\\\
AB=\cfrac{-6 \pm \sqrt{520}}{2}\implies AB=\cfrac{-6 \pm \sqrt{4\cdot 130}}{2}
\\\\\\
AB=\cfrac{-6 \pm \sqrt{2^2\cdot 130}}{2}\implies AB=\cfrac{-6 \pm 2\sqrt{130}}{2}
\\\\\\
AB=-3\pm\sqrt{130}\implies AB=
\begin{cases}
\boxed{-3+\sqrt{130}}\\\\
-3-\sqrt{130}
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since the distance AB cannot be a negative value, thus is not -3-√(130).

3 0
3 years ago
Read 2 more answers
Memory module consists of 9 chips. The device is designed with redundancy so that it works even if one of its chips is defective
soldier1979 [14.2K]

Answer:

a) P[C]=p^n

b) P[M]=p^{8n}(9-8p^n)

c) n=62

d) n=138

Step-by-step explanation:

Note: "Each chip contains n transistors"

a) A chip needs all n transistor working to function correctly. If p is the probability that a transistor is working ok, then:

P[C]=p^n

b) The memory module works with when even one of the chips is defective. It means it works either if 8 chips or 9 chips are ok. The probability of the chips failing is independent of each other.

We can calculate this as a binomial distribution problem, with n=9 and k≥8:

P[M]=P[C_9]+P[C_8]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)\\\\P[M]=p^{8n}(p^{n}+9(1-p^n))\\\\P[M]=p^{8n}(9-8p^n)

c)

P[M]=(0.999)^{8n}(9-8(0.999)^n)=0.9

This equation was solved graphically and the result is that the maximum number of chips to have a reliability of the memory module equal or bigger than 0.9 is 62 transistors per chip. See picture attached.

d) If the memoty module tolerates 2 defective chips:

P[M]=P[C_9]+P[C_8]+P[C_7]\\\\P[M]=\binom{9}{9}P[C]^9(1-P[C])^0+\binom{9}{8}P[C]^8(1-P[C])^1+\binom{9}{7}P[C]^7(1-P[C])^2\\\\P[M]=P[C]^9+9P[C]^8(1-P[C])+36P[C]^7(1-P[C])^2\\\\P[M]=p^{9n}+9p^{8n}(1-p^n)+36p^{7n}(1-p^n)^2

We again calculate numerically and graphically and determine that the maximum number of transistor per chip in this conditions is n=138. See graph attached.

6 0
4 years ago
Bob recorded the number of hours each person watched TV in a week. He then organized the information in a frequency table.​
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Answer:

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Step-by-step explanation:

6 0
3 years ago
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