19. Perimeter of rectangle = 2(l + b)
l = 25m
b = 16m
Perimeter of rectangular park = 2 (25 + 16)
= 50 + 32
= 82m
Perimeter of square park = 82m
(given that, perimeter of rectangular and square park are equal)
Perimeter of square = 4a
4a = 82
a = 82/4
a = 20.5m
Area of square park = a²
= 20.5²
= 420.25m²
20. Perimeter of regular hexagon = 6a
a = 2.5
6a = 6 × 2.5
= 15cm
21. Perimeter of regular decagon = 10a
a = 8
10a = 10 × 8
= 80cm
Answer:
Step-by-step explanation:
We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).
First, recall that the equation of a circle is given by:
Where (<em>h, k</em>) is the center and <em>r</em> is the radius.
Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:
Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:
Solve for <em>r: </em>
<em />
<em />
Simplify. Thus:
Finally, add:
We don't need to take the square root of both sides, as we will have the square it again anyways.
Therefore, our equation is:
9514 1404 393
Answer:
(B) 4
Step-by-step explanation:
Consider the units column. The only sum of 3 and a single digit that will end in 1 is the sum ...
3 + 8 = 11
This tells you A = 8, so the top number is 1983, and the middle number is B78.
Considering the first two columns, we know that 83 +78 = 161, so there must be a carry of 1 into the third column. That makes it have the sum ...
1 + 9 + B = <something ending in 4>
We know the something cannot be 04 or 24, so must be 14. Then ...
10 + B = 14 ⇒ B = 4
__
So, the whole sum is ...
1983 +478 = 2461
and the letter values are ...
C2 + a2 +2 = b
Would be the new formula
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