Sorry this isnt an answer but this is a lot of work, if you really need it answered make it worth more points :)
Answer:
1.80 x 10^24 atoms
Explanation:
3moles × 6.022×10^23 atoms/mole
Answer:
99.56 g.
Explanation:
- The balanced reaction is:
<em>3Ca(NO₃)₂ + 2Na₃PO₄ → 6NaNO₃ + Ca₃(PO₄)₂.</em>
It is clear that 3.0 moles of Ca(NO₃)₂ react with 2.0 moles of Na₃PO₄ to produce 6.0 moles of NaNO₃ and 1.0 mole of Ca₃(PO₄)₂.
- We need to calculate the no. of moles of 96.1 g of Ca(NO₃)₂:
n = mass/molar mass = (96.1 g)/(164.088 g/mol) = 0.5857 mol.
<u><em>Using cross multiplication:</em></u>
3.0 moles of Ca(NO₃)₂ produce → 6.0 moles of NaNO₃.
0.5857 moles of Ca(NO₃)₂ produce → ??? moles of NaNO₃.
∴ The no. of moles of NaNO₃ = (6.0 mol)(0.5857 mol)/(3.0 moles) = 1.171 mol.
<em>∴ The no. of grams of NaNO₃ = (no. of moles of NaNO₃)(molar mass)</em> = (1.171 mol)(84.99 g/mol) = <em>99.56 g.</em>
<h3>Answer:</h3>
2.6 × 10⁻³ g (Or) 0.0026 g
<h3>Data Given;</h3>
Mass of Oxygen = 1.38 × 10⁻³ g
Mass of Silicon = 0.00122 g = 1.22 × 10⁻³ g
<h3>Solution:</h3>
The total weight of grain of sand is calculated by adding the masses of Oxygen and Silicon as,
Total Weight = Mass of Oxygen + Mass of Silicon
Putting values,
Total Weight = 1.38 × 10⁻³ g + 1.22 × 10⁻³ g
Total weight = 2.6 × 10⁻³ g
Or,
Total weight = 0.0026 g