Answer:
A sample of an ideal gas has a volume of 2.21 L at 279 K and 1.01 atm. Calculate the pressure when the volume is 1.23 L and the temperature is 299 K.
You need to apply the ideal gas law PV=nRT
You have the pressure, P=1.01 atm
you have the volume, V = 2.21 L
The ideal gas constant R= 0.08205 L. atm/ mole.K at 273 K
find n = PV/RT = (1.01 atm x 2.21 L / 0.08205 L.atm/ mole.K x 273 K)
n= 0.1 mole, Now find the pressure for n=0.1 mole, T= 299K and
L=1.23 L
P=nRT/V= 0.1mole x 0.08205 (L.atm/ mole.K x 299 k)/ 1.23 L
= 1.994 atm
Explanation:
Answer:
MgCl2 (s) + Li2CO3 (s) ==> MgCO3 (s) + 2LiCl (aq)
Double Replacement
Explanation:
MgCl2 (s) + Li2CO3 (s) ==> MgCO3 (s) + 2LiCl (aq)
Double Replacement
Halogens are Soluble
Carbonates are Insoluble
This reaction DOES take place.
Answer:
Do you have options of answers for this question
Answer:
D) 2000 cm^3
Explanation:
V=Length× Width× Height =40cm ×10cm ×5cm=2000 cm^3
Note: It will be cm^3 not cm.
Hope, this helps you.
